Chapter 6, Problem 6O.16E

(a)

Interpretation Introduction

Interpretation:

Three electrolytic cells containing solutions of ${\text{CuNO}}_{\text{3}}\text{,}{\text{Sn(NO}}_{\text{3}}{\text{)}}_{\text{2}}\text{and}{\text{Fe(NO}}_{\text{3}}{\text{)}}_{\text{3}}$ respectively are connected in series. A current of 3.5 A is passed through the cell until 6.10 g of copper has been deposited in the first cell. The masses of tin and iron are deposited has to be determined.

Concept Introduction:

The same quantity of electricity passes through solutions of different electrolytes, the amount of the substances liberated at the electrodes are directly proportional to their chemical equivalents is known as” Faraday’s second law”. It can be expressed as follows;

  $\frac{{\text{W}}_{\text{1}}}{{\text{E}}_{\text{1}}}\text{=}\frac{{\text{W}}_{\text{2}}}{{\text{E}}_{\text{2}}}$

(b)

Interpretation Introduction

Interpretation:

Three electrolytic cells containing solutions of ${\text{CuNO}}_{\text{3}}\text{,}{\text{Sn(NO}}_{\text{3}}{\text{)}}_{\text{2}}\text{and}{\text{Fe(NO}}_{\text{3}}{\text{)}}_{\text{3}}$ respectively are connected in series. A current of 3.5 A is passed through the cell until 6.10 g of copper has been deposited in the first cell. The masses of tin and iron are deposited has to be determined.