The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified. Concept Introduction: Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor. Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid. Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

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Answer 1

Question

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

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Experiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.

Answer 2

Question

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

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Answer 3

Question

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Expert Solution & Answer

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Answer 4

Question

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Expert Solution & Answer

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Answer 5

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Answer 6

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

Answer 7

Chapter 6, Problem 6A.2AST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 6 - Prob. 6A.1AST Ch. 6 - Prob. 6A.1BST Ch. 6 - Prob. 6A.2AST Ch. 6 - Prob. 6A.2BST Ch. 6 - Prob. 6A.3AST Ch. 6 - Prob. 6A.3BST Ch. 6 - Prob. 6A.1E Ch. 6 - Prob. 6A.2E Ch. 6 - Prob. 6A.3E Ch. 6 - Prob. 6A.4E

Solution Summary: The author explains that Bronsted acids and bases in both reactants and products in the given proton transfer equilibrium have to be identified.

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