Chapter 6, Problem 6F.3E

Interpretation Introduction

Interpretation:

The $pHof9.78\times {10}^{-8}MKOH\left(aq\right)$ has to be calculated.

Concept Introduction:

The contribution of autoprotolysis of water to the calculation of $pH$ of very dilute solutions of strong acid and bases must be taken into consideration.

For very dilute solutions of strong acid, the given below quadratic equation should be used.

  ${\left[H_3{O}^{+}\right]}^2-{\left[HA\right]}_{Initial}\left[H_3{O}^{+}\right]-K_W=0$

For very dilute solutions of strong base, the given below quadratic equation should be used.

  ${\left[H_3{O}^{+}\right]}^2+{\left[B\right]}_{Initial}\left[H_3{O}^{+}\right]-K_W=0$