Chapter 6, Problem 6.67SP

Interpretation Introduction

Interpretation:

The number of kilograms of ${\text{TiO}}_{\text{2}}$ can be prepared from $\text{5}\text{.60kg}$ of ${\text{TiCl}}_{\text{4}}$ has to be calculated.

Concept Introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles can be calculated as:

Number of moles =$\frac{\text{mass}\text{of}\text{the}\text{substance}}{\text{molecular}\text{weight}\text{of}\text{the}\text{substance}}$

Number of kilograms of an atom is represented as:

$\text{no of kgs of an atom=total}\text{mass}\text{of}\text{the}\text{mineral×}\frac{\text{molecular}\text{weight}\text{of}\text{mineral}}{\text{molecular}\text{weight}\text{of the another mineral}}$