Chapter 6, Problem 6.61SP

Interpretation Introduction

Interpretation:

The number of kilograms of iron are present in $\text{105}\text{kg}$ of hematite has to be calculated.

Concept Introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles can be calculated as:

Number of moles =$\frac{\text{mass}\text{of}\text{the}\text{substance}}{\text{molecular}\text{weight}\text{of}\text{the}\text{substance}}$

Percentage of element= $\frac{\text{no}\text{of}\text{moles}\text{of}\text{element × atomic}\text{mass}\text{of}\text{element}}{\text{molecular mass}\text{of}\text{mineral}\text{or}\text{ore}}\text{×100\%}$

The atomic weight of the element can be calculated as $\text{\%}\text{of}\text{atom×mol}\text{weight}\text{of}\text{ore}$ to give the actually weight of the element present in the ore.