Chapter 6, Problem 6.60SP

Interpretation Introduction

Interpretation:

The number of kilograms $\left(\text{Kgs}\right)$ of rutile are needed to produce $\text{100}\text{.0 kg of Ti}$ has to be calculated.

Concept Introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles can be calculated as:

Number of moles =$\frac{\text{mass}\text{of}\text{the}\text{substance}}{\text{molecular}\text{weight}\text{of}\text{the}\text{substance}}$

Number of kilograms of an atom is represented as:

$\text{no of kgs of an atom = total}\text{mass}\text{of}\text{the}\text{mineral × }\frac{\text{molecular}\text{weight}\text{of}\text{mineral}}{\text{atomic}\text{weight}\text{of the element}}$