Chapter 6, Problem 6.137CHP

Interpretation Introduction

Interpretation:

The concentration of a ${\text{KMnO}}_{\text{4}}$ solution if $\text{22}\text{.35}\text{mL}$ solution reacts with $\text{0}\text{.5170}\text{g}$ of oxalic acid has to be calculated.

Concept introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles = $\frac{\text{given}\text{mass of the element}}{\text{atomic}\text{mass}\text{of}\text{element}}$

The amount mass in grams can be calculated as:

The amount mass in grams = $\text{No of moles of element ×}\text{atomic}\text{mass}\text{of}\text{element}$

Molarity:

The molarity of the solution can be determined as the number of moles of solute per one liter solution

Molarity =$\frac{\text{no}\text{.}\text{of}\text{moles}\text{of}\text{solute}}{\text{no}\text{.}\text{of}\text{litres}\text{of}\text{solution}}$