Chapter 6, Problem 6.112SP

Interpretation Introduction

Interpretation:

The number of litres of ${\text{KMnO}}_{\text{4}}$ solution is needed to react completely with $\text{3}\text{.225}\text{g}\text{of oxalic acid}$ has to be calculated.

Concept Introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles of ${\text{H}}_{\text{2}}{\text{C}}_2{\text{O}}_{\text{4}}$= $\frac{\text{given}\text{mass}\text{of}{\text{H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}}{\text{atomicmass}\text{of}{\text{H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}}$

The volume required = $\frac{\text{number}\text{of}\text{moles}\text{of}{\text{KMnO}}_{\text{4}}}{\text{Concentration of}{\text{KMnO}}_{\text{4}}}$