Chapter 6, Problem 6.64SP

(a)

Interpretation Introduction

Interpretation:

The given equation has to be balanced.

Concept Introduction:

Balanced equation is a representation of a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

• Step 1: Write the unbalanced equation
• Step 2: Find the coefficient to balance the equation.
• The coefficient should be reduced to the smallest whole number

(b)

Interpretation Introduction

Interpretation:

Mass of oxygen needed to react with $25g$ of $Mg$ and mass of $MgO$ that will result also has to be determined.

Concept Introduction:

Molecular weight is the sum of weights of all the atoms in a molecule.

One mole of any substance is the amount whose mass in grams is numerically equal to the substances atomic or weight. One mole contains Avogadro’s number of atoms $(6.023\times {10}^{23})$

Number of moles can be calculated by using the below equation,

$Numberofmoles=\frac{Mass\times 1mol}{Molarmass}$

Mass can be calculated by using the below equation,

$Mass=\frac{Numberofmoles\times Molarmass}{1mol}$

(c)

Interpretation Introduction

Interpretation:

Mass of $Mg$ needed to react with $25g$ of $O_2$ and mass of $MgO$ that will result also has to be determined.

Concept Introduction:

Molecular weight is the sum of weights of all the atoms in a molecule.

One mole of any substance is the amount whose mass in grams is numerically equal to the substances atomic or weight. One mole contains Avogadro’s number of atoms $(6.023\times {10}^{23})$

Number of moles can be calculated by using the below equation,

$Numberofmoles=\frac{Mass\times 1mol}{Molarmass}$

Mass can be calculated by using the below equation,

$Mass=\frac{Numberofmoles\times Molarmass}{1mol}$