Chapter 6, Problem 6.110SP

Interpretation Introduction

Interpretation:

The number of grams of ${\text{K}}_{\text{2}}{\text{CO}}_{\text{3}}$ needed to neutralize the acid reaction has to be calculated.

Concept Introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles of $\text{HBr}$= $\text{Conc}\text{. of HBr }\text{× Vol}\text{. of HBr }$

The number of moles of ${\text{K}}_{\text{2}}{\text{CO}}_{\text{3}}$ required=$\frac{\text{number}\text{of}\text{moles}\text{of}\text{HBr}}{\text{2}}$