Chapter 6, Problem 6.136CHP

Interpretation Introduction

Interpretation:

The balanced equation and mass in grams and volume in liters of the ${\text{CO}}_{\text{2}}$ produced from $\text{66}\text{.3}\text{g}\text{of}\text{glucose}$ has to be calculated.

Concept introduction:

Number of moles:

One mole is the equal to number of atoms in $\text{12g}$ of carbon $\text{-12}$ which is equal to $\text{6}{\text{.023×10}}^{\text{23}}$ atoms. This is also known as Avogadro number.

Number of moles = $\frac{\text{given}\text{mass of the element}}{\text{atomic}\text{mass}\text{of}\text{element}}$

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

• Step 1: Write the unbalanced equation
• Step 2: Find the coefficient to balance the equation.
• The coefficient should be reduced to the smallest whole number

Amount mass in grams

The amount mass in grams can be calculated as:

The amount mass in grams = $\text{No of moles of element ×}\text{atomic}\text{mass}\text{of}\text{element}$