Chapter 6, Problem 6.113SP

Interpretation Introduction

Interpretation:

Molarity of a solution made by dissolving $12g$ of oxalic acid to give $400mL$ of solution has to be determined.

Volume in milliliters of $0.100MKOH$ needed to titrate $25mL$ of oxalic acid has to be determined.

Concept introduction:

• Molarity $\left(\text{M}\right)$ is the ratio of number of moles of solute to volume in liters is given by $\text{Molarity=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Liters}\text{of}\text{solution}}$

Unit is $mol/L$

• Number of moles can be calculated by using,

$\text{Number}\text{of}\text{moles=}\frac{\text{Mass}\text{of}\text{solute}\times \text{1}\text{mol}}{\text{MW}}$