Essentials of Materials Science and Engineering, SI Edition
Essentials of Materials Science and Engineering, SI Edition
4th Edition
ISBN: 9781337672078
Author: ASKELAND, Donald R., WRIGHT, Wendelin J.
Publisher: Cengage Learning
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Chapter 6, Problem 6.46P
Interpretation Introduction

Interpretation:

The Flexural strength and Flexural modulus should be calculated for given data of a bar of Al2O3.

Concept introduction:

The ability of any specimen to undergo deformation under the influence of load is known as a Flexural strength.

We can determine the flexural strength with the help of below-mentioned formula:

σBend=3FL2wh2

In the above-mentioned formula,

  • F = the fracture
  • L= the distance between the two points
  • w = width of the specimen
  • h = height of the specimen

The ratio of strength and stress in deformation is known as Flexural Modulus.

We can determine the flexural modulus with the help of below mentioned formula:

Ebend=L3F4 wh3δ

In the above mentioned formula,

  • F = the fracture
  • L= the distance between the two points
  • w = width of the specimen
  • h = height of the specimen
  • δ = the deflection

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A gear has a gear wheel with 16 teeth. The gear should be dimensioned for the highest and lowest gear ratio. Looking for output power, torque, speed?nin= 2000 rpmmin = 30Nmn=0,9a max= 450 mmModule 4Gear limitsz1                        z213                       13-1614                       14-2615                       15-4516                       16-10117                       17-131418                        18-…..I have calculate but I can’t get the right answers…..√16 =459x60/56x57=1.1  lowest59x60/13x13=20,94 highestnut=2000/1.1= 1818rpmnut=2000/20.94=95.5 rpmMut=1.1x30=33 NmMut=20.94x30=628,2 Nm(Right answer)LowestZ=13, M=24,4Nm, n=2462 rpmHighestZ=92, M=172,5Nm, n=347,8 rpmP=5655W on both
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