Can you show how this answer was found? For the RLC circuit shown, the switch is initially in the open position and closesat time t = 0. The component values are R=4k, L=525mH, C=2nF, andthe source voltage is V₂ =7V. Find the value of the voltage V (t) at time t =66us. Enter your answer in units of Volts.You AnsweredVsIRRt=0LCorrect Answer4.6971 margin of error +/- 1%+ A

Answered: Image /qna-images/answer/4d958cc5-0561-48b8-b54f-12be34f64ccc.jpg

Answered: For the RLC circuit shown, the switch…

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter19: Capacitors

Section: Chapter Questions

Problem 2PA: You are an electrician working in an industrial plant. You discover that the problem with a certain...

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You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.
In the circuit below, Find the voltage across the inductor at time t = 0.000909 s. The values are V1 = 146V, R = 4.4 ohms, L =0.02 henries
1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.
For the circuit in the figurea) Determine the time constant.b) Write the mathematical expression for IL, VL and VR, after the switch is closed.c) Determine IL, VL for one, three and five time constants.d) Draw the waveforms of IL, VL and VR.
Using the series circuit in Figure 3 consisting of a voltage source V, the resistor R and the fully uncharged capacitor C, how to find the value of the capacitance C considering as known data the time constant of the circuit T and the value of the resistor R? V ww R
Consider the RC circuit in Figure 2 below. Assuming the switch has been open for a long time before it is closed, fill in a table providing the current through each component and the voltage across each component immediately after the switch is closed, and a very long time after the switch is closed. Next, figure out the time constant for the circuit. (Hint: Assign currents to each branch. Set up the necessary KVL and KCL equations. Eliminate all but one variable to get an equation for just one of the currents. You shouldn’t have to solve this equation to recognize the time constant!)
This is a practice question from my Introduction to Circuits course. Thank you for the explanation.
A 1-H inductor is connected in series with a 6-ohm resistor. If the connection is energized from a 9-V DC source, determine the current (in amperes) through the circuit for a long time. The initial current is 100 mA. Express your answers accurate to four decimal places. No need to put the units.
For the series RL circuit shown in the figure below, answer the following questions and justify your answer.If the current is kept constant, does the coil have inductance?If the current is kept constant, does the coil affect the current value?Can the reverse emf ever be greater than the battery emf?
Energy stored in capacitor. Answer it in 30 mins. Draw/sketc the problem thank you. Write the basic equation before the soln. Thank you
show the complete solution for this problem, thanks!
in the image below, Please find the voltage across the resistor at time t = 0.00069 seconds. The energy stored in the capacitor and inductor at t=0 is 0 Joules. The values are I1 = 75 A, R = 0.059 ohms, L = 0.01 Henries, C = 0.04 Farads.

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