= cos (2π x 10t+ 0) where 0 is random with a probability densityE [0, 2π), and f(0) = 0 otherwise. v,(t) passes through a linear filter below.2. Consider a random process v(t)function f(0) = 1/(2) forvi(t)-H(f)vo(t)Determine(a) (5%) vo(t);(b) (10%) autocorrelation function of v(t);(c) (8%) power spectral density function of vo(t);(d) (7%) power of vo(t).1=H(f)2πf2+1

Here are my responses to your questions. If you find my answers satisfactory, I would appreciate a…

Answered: = cos (2π x 10t+ 0) where 0 is random…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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*3. A continuous time signal, x(t) = sin(20t) + cos(40t), is sampled uniformly at intervals of T to obtain a discrete time signal, x(n) = sin(an/5) + cos(2rn/5). a) What is the value of T assuming no aliasing has occurred? b) Assume both frequency components have been aliased. In this case, is your choice of T unique? If not, specify some choices of T consistent with the information given.
2. (5 points) Consider the DT signal x[n] given by x[n] = −n²u[n] Characterize the signal as periodic/aperiodic (1 pt), even/odd/neither even nor odd (1 pt), and en- ergy/power/neither energy nor power (3 pts). You must substitute the signal into the energy and power equations and must make a well reasoned argument.
The sequence x(n) = 3sin(0.5πn) was created by sampling a continuous sinusoid at a sampling rate of kHz. What was the frequency (in Hz) of the continuous sinusoid, assuming no aliasing? Let: fs=28 khz
[3] x(t) is a continuous time (CT), Periodic signal, with a period T. The equation for a single period is: x(t)={Acos(2rtT); -T4stsT40 ;otherwise Find an expression for the fifth harmonic frequency when A=1 and T=8 (Hint: to evaluate the integration express the cosine term as two exponential terms using Euler's rule)
A continuous time signal, x(t) = sin(20πt) + cos(40πt), is sampled uniformly at intervals of T to obtaina discrete time signal,x(n) = sin(πn/5) + cos(2πn/5).a) What is the value of T assuming no aliasing has occurred?b) Assume both frequency components have been aliased. In this case, is your choice of T unique? If not,specify some choices of T consistent with the information given
Please answer part D, thanks!
For the sampled signal ws(n) = 12 + 8 cos((1/4)πn + 0.1) + 12 sin((3/4)πn − 0.2) generated by sampling w(t) at t = nT at a sampling frequency of fs = 1/T = 600 Hz, find expressions for w(t) with the following restrictions:a) Component frequencies range from 0 Hz to 300 Hzb) Component frequencies range from 300 Hz to 600 Hzc) Component frequencies range from 600 Hz to 900 Hz
QI The DFS of a signal x{n] and its coefficients ay are both periodic of some value N. Answer the following 2) To find the x{n), 0 Sn < N -1 given a,, 0 < k
For the signal x(t) = 12 cos(2π350t + π/4), find the signals y(t) for each sampling frequency which will generate the same samples of x(t) but with the lowest positive frequency. (Hint: Sample at t = nT, fs = 1/T)a) fs = 50 Hertz b) fs = 125 Hertz c) fs = 500 Hertz d) fs = 1000 Hertz
Problem 2 Consider the signal n ≤2 y(n) = {0, elsewhere
Consider a real, odd, and periodic signal a(t) given by: 5 x(t) = E ) sin(krt) k=0 This signal is sampled at the rate T = 0.2 sec/sample. Now, what happens if we like to reconstruct this signal back from its samples? Is this possible? Do we lose any information about the signal when we sampled the signal at the rate T = 0.2 sec/sample? Comment on why the Nyquist sampling condition is F, > 2F,maz where Fmar is the highest frequency in the signal to be sampled, rather than simply F, = 2Fmaz-.
Solve using kmap F(A,B,C,D) = sigma m ( 0 , 4, 6 ,8 , 9 ) + d(1 , 2 )

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