The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to 1/20 of its initial voltage? Take R₁ = 2.00 Q R₂=4.00 Q, R 3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.) R₁ R₂ 33 R₂
The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to 1/20 of its initial voltage? Take R₁ = 2.00 Q R₂=4.00 Q, R 3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.) R₁ R₂ 33 R₂
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter21: Resistive-capacitive Series Circuits
Section: Chapter Questions
Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...
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![The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to
1/20 of its initial voltage? Take R₁ = 2.00 Q, R₂=4.00 Q, R3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must
be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.)
E
R₂
R₂
BA](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9afe4d0e-2011-4de8-90c5-4b598cb1f56d%2Fbbaa338e-3fdc-41c7-9daa-472007cb247a%2F7i9fkaa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to
1/20 of its initial voltage? Take R₁ = 2.00 Q, R₂=4.00 Q, R3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must
be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.)
E
R₂
R₂
BA
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