Chapter 6, Problem K6.1KP

Interpretation Introduction

(a)

Interpretation:

The modulus of elasticity of mentioned material and its allowed tensile stress needs to be determined.

Concept Introduction:

Modulus of elasticity is as per number of aluminum alloy. Tensile stress is equal to half of the tensile yield stress.

Interpretation Introduction

(b)

Interpretation:

The tensile stress and axial load applied on the rod needs to be determined.

Concept Introduction:

Tensile stress can be calculated as follows:

$\sigma =e\times E$

Here,

e = strain

E = Modulus of elasticity.

Similarly, axial load $\left(F\right)= \sigma \times A$

Here,

$\sigma$ = axial stress

A = Cross sectional area

Interpretation Introduction

(c)

Interpretation:

The calculated tensile stress needs to be compared with the allowed tensile stress. The absolute value of elongation of rod needs to be determined.

Concept Introduction:

Elongation of rod for allowable tensile stress is calculated as follows:

$\Delta l=S\times \frac{L}{E}$

Here,

$\Delta l$ = Elongation

S = allowable tensile stress

L = length of rod

E = modulus of elasticity.