Consider the circuit in Figure 6.18. The circuit parameters are V + = 3.3 V , V B B = 2.455 V , R B = 80 kΩ , and R C = 7 kΩ . The transistor parameters are β = 110 , V B E (on) = 0.7 V , and V A = 80 V . (a) Determine I C Q and V E C Q . (b) Find g m , r π , and r o . (c) Determine the small−signal voltage gain A υ = υ o / υ s . (d) Find the small−signal input and output resistances R i and R o , respectively. (Ans. (a) I C Q =0 .2mA , V E C Q = 1.9 V ; (b) g m = 7.692 mA/V , r π = 14.3 kΩ , r o = 400 kΩ ; (c) A υ = − 8.02 ; (d) R i = 94.3 kΩ , R o = 6.88 kΩ )
Consider the circuit in Figure 6.18. The circuit parameters are V + = 3.3 V , V B B = 2.455 V , R B = 80 kΩ , and R C = 7 kΩ . The transistor parameters are β = 110 , V B E (on) = 0.7 V , and V A = 80 V . (a) Determine I C Q and V E C Q . (b) Find g m , r π , and r o . (c) Determine the small−signal voltage gain A υ = υ o / υ s . (d) Find the small−signal input and output resistances R i and R o , respectively. (Ans. (a) I C Q =0 .2mA , V E C Q = 1.9 V ; (b) g m = 7.692 mA/V , r π = 14.3 kΩ , r o = 400 kΩ ; (c) A υ = − 8.02 ; (d) R i = 94.3 kΩ , R o = 6.88 kΩ )
Solution Summary: The circuit for pnp common emitter is shown in Figure 1.
Consider the circuit in Figure 6.18. The circuit parameters are
V
+
=
3.3
V
,
V
B
B
=
2.455
V
,
R
B
=
80
kΩ
, and
R
C
=
7
kΩ
. The transistor parameters are
β
=
110
,
V
B
E
(on)
=
0.7
V
, and
V
A
=
80
V
. (a) Determine
I
C
Q
and
V
E
C
Q
. (b) Find
g
m
,
r
π
, and
r
o
. (c) Determine the small−signal voltage gain
A
υ
=
υ
o
/
υ
s
. (d) Find the small−signal input and output resistances
R
i
and
R
o
, respectively. (Ans. (a)
I
C
Q
=0
.2mA
,
V
E
C
Q
=
1.9
V
; (b)
g
m
=
7.692
mA/V
,
r
π
=
14.3
kΩ
,
r
o
=
400
kΩ
; (c)
A
υ
=
−
8.02
; (d)
R
i
=
94.3
kΩ
,
R
o
=
6.88
kΩ
)
Can you rewrite the solution because it is
unclear?
Q2
AM
①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt)
$4+) = 45
=
*cos 10000 πt.
8 cos wat + 4 cosat + 4 cos Wat coswet.
j1000016
+4e
-j10000πt j11000Rt
j gooort -j 9000 πt
+
e
+e
j sooort
te
+e
J11000 t
+ e
te
j 12000rt.
-J12000 kt
+ с
= 8th S(W- 100007) + 8 IS (W-10000)
<&(w) =
USB
-5-5
-4-5-4
b) Pc 2² = 64
PSB =
42
+ 4
2
Pt Pc+ PSB =
y = Pe
c) Puss =
PLSB =
= 32
4² = 8 w
32+ 8 =
× 100% = 140
(1)³×2×2
31
= 20%
x 2 = 3w
302
USB
4.5 5 5.6 6
ms Ac = 4 mi
= 0.5
mz Ac = 4
५
M2
=
=0.5
A. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and
Manchester code.
Data sequence= (00110100)
B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of
50 dB. If the message is a single tone with fm-5 kHz. Determine:
1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio.
2) Minimum required system bandwidth.
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