EBK ESSENTIAL ORGANIC CHEMISTRY
EBK ESSENTIAL ORGANIC CHEMISTRY
3rd Edition
ISBN: 8220100659461
Author: Bruice
Publisher: PEARSON
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Chapter 6, Problem 60P
Interpretation Introduction

Interpretation:

The compound which will be more hydrated should be determined.

Concept introduction:

Carbocation: It is carbon ion that bears a positive charge on it.

Leaving group: It is a fragment that leaves from a substrate with a pair of electrons via heterolytic bond cleavage.

Carbocation stability order:

EBK ESSENTIAL ORGANIC CHEMISTRY, Chapter 6, Problem 60P

Resonance stabilization: Due to the delocalization of electrons within the molecule the overall energy becomes lower and makes that molecule more stable.

Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.

Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.

Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.

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32. Consider a two-state system in which the low energy level is 300 J mol 1 and the higher energy level is 800 J mol 1, and the temperature is 300 K. Find the population of each level. Hint: Pay attention to your units. A. What is the partition function for this system? B. What are the populations of each level? Now instead, consider a system with energy levels of 0 J mol C. Now what is the partition function? D. And what are the populations of the two levels? E. Finally, repeat the second calculation at 500 K. and 500 J mol 1 at 300 K. F. What do you notice about the populations as you increase the temperature? At what temperature would you expect the states to have equal populations?
30. We will derive the forms of the molecular partition functions for atoms and molecules shortly in class, but the partition function that describes the translational and rotational motion of a homonuclear diatomic molecule is given by Itrans (V,T) = = 2πmkBT h² V grot (T) 4π²IKBT h² Where h is Planck's constant and I is molecular moment of inertia. The overall partition function is qmolec Qtrans qrot. Find the energy, enthalpy, entropy, and Helmholtz free energy for the translational and rotational modes of 1 mole of oxygen molecules and 1 mole of iodine molecules at 50 K and at 300 K and with a volume of 1 m³. Here is some useful data: Moment of inertia: I2 I 7.46 x 10- 45 kg m² 2 O2 I 1.91 x 101 -46 kg m²
K for each reaction step. Be sure to account for all bond-breaking and bond-making steps. HI HaC Drawing Arrows! H3C OCH3 H 4 59°F Mostly sunny H CH3 HO O CH3 'C' CH3 Select to Add Arrows CH3 1 L H&C. OCH3 H H H H Select to Add Arrows Q Search Problem 30 of 20 H. H3C + :0: H CH3 CH3 20 H2C Undo Reset Done DELL

Chapter 6 Solutions

EBK ESSENTIAL ORGANIC CHEMISTRY

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