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(a)
Interpretation:
The major product for reaction between
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Electrophilic addition: It is a type of addition reaction in which the pi bond present in the molecule breaks as the electrophile approaches and results in the formation of product with sigma bond.
Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms.
Reduction Reaction: It is just opposite of oxidation reaction which involves removal of oxygen atoms or addition of hydrogen atoms and addition of electrons.
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
(b)
Interpretation:
The major product for reaction between
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Electrophilic addition: It is a type of addition reaction in which the pi bond present in the molecule breaks as the electrophile approaches and results in the formation of product with sigma bond.
Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms.
Reduction Reaction: It is just opposite of oxidation reaction which involves removal of oxygen atoms or addition of hydrogen atoms and addition of electrons.
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
(c)
Interpretation:
The major product for reaction between
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Electrophilic addition: It is a type of addition reaction in which the pi bond present in the molecule breaks as the electrophile approaches and results in the formation of product with sigma bond.
Addition of halogen to an
(d)
Interpretation:
The major product for reaction between
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Electrophilic addition: It is a type of addition reaction in which the pi bond present in the molecule breaks as the electrophile approaches and results in the formation of product with sigma bond.
Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms.
Acid Catalyzed Hydration Reaction: The reaction involves breaking of phi bonds between carbon-carbon multiple bonds and addition of alcohol to more substituted position of carbon in the molecule.
First step is the acid donates proton to the alkene which leads to the formation of more stable carbo cation.
Then, the water is added to the given alkene through acid catalyzed reaction where the water gets added to the carbo cation finally, the removal of one proton from oxonium ion (oxygen with one positive charge) using water results in the formation of product.
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
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Chapter 6 Solutions
EBK ESSENTIAL ORGANIC CHEMISTRY
- Using line angle formulas, draw thestructures of and name four alkanes that have total of 7carbons, one of which is tertiary.Please explain this in detail and can you also explain how to approach a similar problem like this as well?arrow_forwardUsing dashed line wedge projections drawthe indicated compounds and indicate whether thecompound you have drawn is R or S.(a) The two enantiomers of 2-chlorobutane. Can you please explain your steps and how you would approach a similar problem. Thank you!arrow_forward5) There are no lone pairs shown in the structure below. Please add in all lone pairs and then give the hybridization scheme for the compound. (8) 10,11 7) 1.2.3 H 4 | 14 8) COC 12 13 H 16 15 H7 9) - 5.6 C 8 H 10) H 1). 2) 3)_ 11) 12) 13) 4)_ 14) 5) 15) 16) 6)arrow_forward
- The sum of the numbers in the name of isA. 11; B. 13; C. 10; D. 12; E. none of the other answers iscorrect. I believe the awnser should be E to this problem but the solution to this problem is D 12. I'm honestly unsure how that's the solution. If you can please explain the steps to this type of problem and how to approach a problem like this it would be greatly appreciated!arrow_forwardConsider the following data for phosphorus: g atomic mass 30.974 mol electronegativity 2.19 kJ electron affinity 72. mol kJ ionization energy 1011.8 mol kJ heat of fusion 0.64 mol You may find additional useful data in the ALEKS Data tab. Does the following reaction absorb or release energy? 2+ + (1) P (g) + e → P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? 00 release absorb Can't be decided with the data given. yes no ☐ kJ/mol (²) P* (8) + + + e →>> P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): ☐ release absorb Can't be decided with the data given. yes no kJ/mol аarrow_forwardThe number of hydrogens in an alkyne that has a main chain of 14carbons to which are attached a cyclobutyl ring, a benzene ring, an–OH group, and a Br is A. 34; B. 35; C. 36; D. 24; E. 43arrow_forward
- Hello! I have a 500 Hz H-NMR for 1,5-bis-(4-methoxyphenyl)-penta-1,4-dien-3-one. I need to label the signals with the corresponding H's. Then, find out if the two alkenes are cis or trans by calculating the J values. I believe that I have the H-NMR labeled correctly, but not sure if I got the J values correct to determine if the two alkenes in the compound will make the compound cis or trans.arrow_forwardWhat is the only possible H-Sb-H bond angle in SbH3?arrow_forwardpls helparrow_forward
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