Materials Science And Engineering Properties
Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 6, Problem 19CQ
To determine

The reason for plastic strain in the thermoplastic polymer.

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The composite bar shown is rigidly attached to the two supports. The left portion of the bar is copper, of uniform cross-sectional area 80 c?^2 and length 30 cm. The right portion is aluminum, of uniform cross-sectional area 20 c?2 and length 20 cm. At a temperature of 26℃ the entire assembly is stress free. The temperature of the structure drops and during this process the right support yields 0.025 mm in the direction of the contracting metal. Determine the minimum temperature to which the assembly may be subjected in order that the stress in the aluminum does not exceed 160 MPa. For copper E = 200 GPa, ? = 17x10^-6/℃, and for Aluminum E = 80 GPa, ? = 23x10^-6/℃.
Question 5 A steel component is subjected to a biaxial state of stress in which both stresses are tensile in nature, and having magnitudes 100 and 60 MPa. The plane at which the resultant stress has maximum obliquity with the normal (in degrees) is
An aluminum alloy [E = 74 GPa; v = 0.33; a = 23.0 x 10-6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 265 mm, a cross-sectional area of A = 5300 mm², and a length of L= 4.2 m. The initial longitudinal normal strain in the plate is zero. After load P is applied and the temperature of the plate has been increased by AT = 57°C, the longitudinal normal strain in the plate is found to be 2920 με. Determine: (a) the magnitude of load P. (b) the change in plate depth Ad. L P Answer: (a) P = i (b) Δd = i kN mm

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Materials Science And Engineering Properties

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