Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 6, Problem 12CQ
To determine
The law used to explain the linear relationship between stress and elastic strain.
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Students have asked these similar questions
The deformation per unit length is called
O a. Strain
O b. Tensile stress
O c. Shear stress
O d. Compressive stress
The radius of Mohr's circle of stress of a strained element is 20 N/mm² and minor principal tensile stress
is 10 N/mm². What is the value of the major principle stress?
The stress in an elastic material is:
A Inversely proportional to the force acting
B
Inversely proportional to the materials yield strength
C Proportional to the displacement
D Inversely proportional to the strain
Chapter 6 Solutions
Materials Science And Engineering Properties
Ch. 6 - Prob. 1CQCh. 6 - Prob. 2CQCh. 6 - Prob. 3CQCh. 6 - Prob. 4CQCh. 6 - Prob. 5CQCh. 6 - Prob. 6CQCh. 6 - Prob. 7CQCh. 6 - Prob. 8CQCh. 6 - Prob. 9CQCh. 6 - Prob. 10CQ
Ch. 6 - Prob. 11CQCh. 6 - Prob. 12CQCh. 6 - Prob. 13CQCh. 6 - Prob. 14CQCh. 6 - Prob. 15CQCh. 6 - Prob. 16CQCh. 6 - Prob. 17CQCh. 6 - Prob. 18CQCh. 6 - Prob. 19CQCh. 6 - Prob. 20CQCh. 6 - Prob. 21CQCh. 6 - Prob. 22CQCh. 6 - Prob. 23CQCh. 6 - Prob. 24CQCh. 6 - Prob. 25CQCh. 6 - Prob. 26CQCh. 6 - Prob. 27CQCh. 6 - Prob. 28CQCh. 6 - Prob. 29CQCh. 6 - Prob. 30CQCh. 6 - Prob. 31CQCh. 6 - Prob. 32CQCh. 6 - Prob. 33CQCh. 6 - Prob. 34CQCh. 6 - Prob. 35CQCh. 6 - Prob. 36CQCh. 6 - Prob. 37CQCh. 6 - Prob. 38CQCh. 6 - Prob. 1ETSQCh. 6 - Prob. 2ETSQCh. 6 - Prob. 3ETSQCh. 6 - Prob. 4ETSQCh. 6 - Prob. 5ETSQCh. 6 - Prob. 6ETSQCh. 6 - Prob. 7ETSQCh. 6 - Prob. 8ETSQCh. 6 - Prob. 9ETSQCh. 6 - At the ultimate tensile strength. (a) The true...Ch. 6 - Prob. 11ETSQCh. 6 - Prob. 12ETSQCh. 6 - Prob. 13ETSQCh. 6 - Prob. 14ETSQCh. 6 - Prob. 15ETSQCh. 6 - Prob. 16ETSQCh. 6 - Prob. 6.1PCh. 6 - Prob. 6.2PCh. 6 - Compare the engineering and true secant elastic...Ch. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - An iron specimen is plastically deformed in shear...Ch. 6 - Prob. 6.7PCh. 6 - Prob. 6.8PCh. 6 - Prob. 6.9PCh. 6 - Prob. 6.10PCh. 6 - Prob. 6.11PCh. 6 - Prob. 6.12PCh. 6 - Prob. 6.13PCh. 6 - Prob. 6.14PCh. 6 - Estimate the elastic and plastic strain at the...Ch. 6 - Prob. 6.16PCh. 6 - Prob. 6.17PCh. 6 - Prob. 6.18PCh. 6 - Prob. 6.19PCh. 6 - Prob. 6.1DPCh. 6 - Prob. 6.2DP
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- An element in plane stress is subjected to stresses o, = -8400 psi, ay = 1100 psi, and ty = 1700 psi (see figure). The material is aluminum with %3D modulus of elasticity E =10,000 ksi and Poisson's ratio v = 0.33. Determine the following quantities: (a) the strains for an element oriented at an angle 30 degrees, (b) the principal strains, and (c) the maximum shear strains. Show the results on sketches of properly oriented elements. Ty Txy Oxarrow_forwardDiscuss the principles of stress and deformation analysis for several kinds of stressesarrow_forward1. For each state of plane stress shown below, i.e., for configurations (a) and (b), indicate whether each component of the state of strain is: = 0 (equal to zero) >0 (greater than zero) <0 (less than zero) The material is linear elastic with Possion's ratio is between (0, 0.5), and the deformations are small. T 30 e X 0 Ex Ey Ez Yxy Yyz Yzx (a) (b) 1° (b) 1xarrow_forward
- A bronze rod is rigidly attached between an aluminum rod and a steel rod as shown in the figure below. Axial loads are applied at the positions indicated. a) Find the maximum value of P that will not exceed a stress in steel of 140 MPa, in bronze of 100 MPa, or in aluminum of 90 MPa. b) Determine the deformation of the bronze rod if the value of P is 22.50 KN. The moduli of elasticity are 200 GPa for steel, 80 GPa for bronze and 70 GPa for aluminum.arrow_forwardStrain = 600 Stress = Strain = 500 Stress = 400 500 300 400 300 200 200 100 100 0.000 0.002 0.004 0.006 Strain 0.00 0.04 0.08 0.12 0.16 0.20 Strain Stress (MPa)arrow_forwardAt a point in a strained material, tensile stress of 100 MPa and compressive stress of 60 MPa are found to be principal stresses Maximum shear stress at that point is: O 60 MPa O 20 MPa O 40 MPa O 80 MPaarrow_forward
- 9 The ratio of direct stress to the corresponding volumetric strain is constant within its elastic limit. The ratio is known as Volumetric strain Bulk modulus Shear modulus Modulus of elasticity Poisson's ratioarrow_forwardStresses that cause change in volume are called (A) hydrostatic stresses (B) deviatoric stresses C) tensile stress D) bending stressarrow_forwardErase Figure 9 In using the method of consistent deformation in analysing structures, the compatibility equation has to be written. Why is this necessary?arrow_forward
- A steel 0.6 inch×1.2 inch steel 90 m long is subjected to a 45 KN tensile load along its lenght.If poison's ratio is 0.3 Find: A. The deformation along its lenght. B. The deformation along its thickness. C. The defirmation along uts width. D. The lateral strain.arrow_forwardThe limit of proportionality in the material of a structural steel member, when subjected to simple tension, is 280 N/mm2. The principal stresses in the member are o, = 122 N/mm2 (Tensile) and 0₂= 60 N/mm² (Compressive). μ = 0.3. According to maximum strain theory, the factor of safety isarrow_forwardThe value of strain if stress is 35 MPa and Youngs modulus 65 MPaarrow_forward
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