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Concept explainers
Interpretation:
The molecule that has linear geometry has to be chosen from the given options.
Concept Introduction:
Information about the number of bonds and types of bonds can be obtained from Lewis structure but the molecular geometry cannot be obtained. Three dimensional arrangement of atoms in a molecule can be given by molecular geometry. Physical and chemical properties are determined by the molecular geometry of the molecule.
Using VSEPR theory and Lewis structure, the molecular geometry of the molecule that contain less number of atoms can be predicted. VSEPR theory uses the information from Lewis structure of the molecule to predict the molecular geometry of the molecule. Main concept of VSEPR theory is that electron pairs that are present in the valence shell adopt arrangement in a way that minimize the repulsion between like charges.
If the central atom contains two electron pairs, then it has to be far apart means, it has to be on opposite side of the nucleus. This means the angle has to be
If the central atom contains three electron pairs, then it has to be far apart means, it has to be on corner of a triangle. This means the angle has to be
If the central atom contains four electron pairs, then it has to be far apart means, it has to be in a tetrahedral arrangement. This means the angle has to be
The collection of valence electron that is present in localized region about central atom in a molecule is known as VSEPR electron group. This may contain two electrons, four electrons, or six electrons. The electron group that contain four and six electrons repel each other.
Tetrahedral VSEPR electron group:
The four electron pairs can be of three VSEPR electron groups. They are 4 bonding electron groups, 3 bonding and 1 nonbonding electron groups, and 2 bonding and 2 nonbonding electron groups. The molecular geometry that is associated with 4 bonding electron groups is tetrahedral. The molecular geometry that is associated with 3 bonding and 1 nonbonding electron groups is trigonal pyramidal. The molecular geometry that is associated with 2 bonding and 2 nonbonding electron groups is angular.
Trigonal planar VSEPR electron group:
The three electron pairs can be of two VSEPR electron groups. They are 3 bonding electron groups, and 2 bonding and 1 nonbonding electron groups. The molecular geometry that is associated with 3 bonding electron groups is trigonal planar. The molecular geometry that is associated with 2 bonding and 1 nonbonding electron groups is angular.
Linear VSEPR electron group:
The two electron pairs can be of only one VSEPR electron groups. It is only 2 bonding electron groups and the geometry associated with it is linear geometry.
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Chapter 5 Solutions
General, Organic, and Biological Chemistry
- I want to know how to do it , please helparrow_forwardHelp me i dont know how to do itarrow_forwardCan you explain how to draw a molecular orbital diagram for the given molecule? It is quite difficult to understand. Additionally, could you provide a clearer illustration? Furthermore, please explain how to draw molecular orbital diagrams for any other given molecule or compound as well.arrow_forward
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- Use the References to access important values if needed for this question. What is the IUPAC name of each of the the following? 0 CH3CHCNH₂ CH3 CH3CHCNHCH2CH3 CH3arrow_forwardYou have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you manipulated and exploited the acid-base chemistry of one or more of the compounds in your mixture to facilitate their separation into different phases. The key to understanding how liquid- liquid extractions work is by knowing which layer a compound is in, and in what protonation state. The following liquid-liquid extraction is different from the one you performed in Experiment 4, but it uses the same type of logic. Your task is to show how to separate apart Compound A and Compound B. . Complete the following flowchart of a liquid-liquid extraction. Handwritten work is encouraged. • Draw by hand (neatly) only the appropriate organic compound(s) in the boxes. . Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4 and 5. • Box 7a requires the solvent (name is fine). • Box 7b requires one inorganic compound. • You can neatly complete this assignment by hand and…arrow_forwardb) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;' The compound has the ff electronic transitions: 0%o* and no a* 1H NMR Spectrum (CDCl3, 400 MHz) 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm 13C{H} NMR Spectrum (CDCl3, 100 MHz) Solvent 80 70 60 50 40 30 20 10 0 ppm ppm ¹H-13C me-HSQC Spectrum ppm (CDCl3, 400 MHz) 5 ¹H-¹H COSY Spectrum (CDCl3, 400 MHz) 0.5 10 3.5 3.0 2.5 2.0 1.5 1.0 10 15 20 20 25 30 30 -35 -1.0 1.5 -2.0 -2.5 3.0 -3.5 0.5 ppm 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppmarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
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