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Concept explainers
Interpretation:
Among the given names for binary compounds, the one that contain incorrect prefix has to be chosen.
Concept Introduction:
Molecular compound that contains only two nonmetallic elements in it is known as Binary molecular compound. Naming a binary molecular compound is similar to that of a binary ionic compound. A major difference is that the binary molecular compound contain numerical prefixes which gives the information about the number of atoms of same kind are present in it.
For naming a binary molecular compound, the element that has lower electronegativity is given first and that is followed by a stem of the name of the nonmetal that is more electronegative and the suffix “-ide”. Numerical prefixes are added to both nonmetals to indicate the number of atoms present in it.
Some binary molecular compounds have names that are no way related to the naming rules. They are common names that are given for the compounds before the systematic rule development.
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Chapter 5 Solutions
General, Organic, and Biological Chemistry
- (Please be sure that 7 carbons are available in the structure )Based on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons. Dept 135 shows peak to be positive at 128.62 and 13.63 Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10.arrow_forward-lease help me answer the questions in the photo.arrow_forwardDefine electronegativity.arrow_forward
- Why do only the immediately adjacent H's show up in the number of peaks? Are there normally peaks for the H's that are 2-3 carbons away?arrow_forwardPlease help me understand this question. Thank you. Organic Chem 1arrow_forwardFor the reaction below, the concentrations at equilibrium are [SO₂] = 0.50 M, [0] = 0.45 M, and [SO3] = 1.7 M. What is the value of the equilibrium constant, K? 2SO2(g) + O2(g) 2SO3(g) Report your answer using two significant figures. Provide your answer below:arrow_forward
- scratch paper, and the integrated rate table provided in class. our scratch work for this test. Content attribution 3/40 FEEDBACK QUESTION 3 - 4 POINTS Complete the equation that relates the rate of consumption of H+ and the rate of formation of Br2 for the given reaction. 5Br (aq) + BrO3 (aq) + 6H (aq) →3Br2(aq) + 3H2O(l) • Your answers should be whole numbers or fractions without any decimal places. Provide your answer below: Search 尚 5 fn 40 * 00 99+ 2 9 144 a [arrow_forward(a) Write down the structure of EDTA molecule and show the complex structure with Pb2+ . (b) When do you need to perform back titration? (c) Ni2+ can be analyzed by a back titration using standard Zn2+ at pH 5.5 with xylenol orange indicator. A solution containing 25.00 mL of Ni2+ in dilute HCl is treated with 25.00 mL of 0.05283 M Na2EDTA. The solution is neutralized with NaOH, and the pH is adjusted to 5.5 with acetate buffer. The solution turns yellow when a few drops of indicator are added. Titration with 0.02299 M Zn2+ requires 17.61 mL to reach the red end point. What is the molarity of Ni2+ in the unknown?arrow_forwardA compound has the molecular formula CH40, and shows a strong IR absorption at 2850-3150 cm. The following signals appear in the 'H NMR spectrum: 1.4 ppm (triplet, 6H), 4.0 ppm (quartet, 4H), 6.8 ppm (broad singlet, 4H). Which of the following structures is consistent with these data? Select the single best answer. OCH CH₂ x OCH2CH3 CH₂OCH3 OH CH₂OCH OH CH, OCH₁ CH₂OCH, CH₂OCH HO OH ° CH₂OCH3arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
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