Chapter 5.1, Problem 5PP

(a)

Interpretation Introduction

Interpretation:

The energy possessed by a single photon having frequency $6.32\times {10}^{20}{s}^{-1}$ needs to be calculated.

Concept introduction:

The energy of each quantum is directly proportional to the frequency ( $\nu$ ) of the radiation.

Answer to Problem 5PP

The Energy of electromagnetic radiation is $41.87\times {10}^{-14}Joule$

Explanation of Solution

Given information:

Frequency = $6.32\times {10}^{20}{s}^{-1}$

Calculation:

$E=hv$

$E$ = Energy of photon

$h$ = plank’s constant

$v$ = Frequency

Putting the values,

$E=6.626\times {10}^{-34}Js\times 6.32\times {10}^{20}{s}^{-1}$

$E=6.626\times 6.32\times {10}^{-34+20}J$

$E=41.87\times {10}^{-14}Joule$