Chapter 5, Problem 58A

Interpretation Introduction

Interpretation:

Line’s color and line’s frequency of Hydrogen is to be determined.

Concept introduction:

The Emission spectrum refers to the range of wavelengths emitted by an atom or compound stimulated by the heat or electric current.

Answer to Problem 58A

Hydrogen Line’s frequency is $6.17\times {10}^{14}{s}^{-1}$

Explanation of Solution

Given:

Emission spectrum of Hydrogen’s wavelength $=486nm.$

Explanations:

Since, the wavelength is 486 nm thus, the color of line is green.

Now,

$v= c/\lambda$

Where

$c$ = speed of light $\left(3\times {10}^{8}m/s\right)$

$v=\frac{3\times {10}^8\text{ m/s}}{486\times {10}^{-9}\text{ m}}=6.17\times {10}^{14}{s}^{-1}$

Conclusion

Hydrogen Line’s frequency is $6.17\times {10}^{14}{s}^{-1}$