Interpretation:
The energy of the photons related to the two bright lines needs to be determined.
Concept introduction:
The relation between energy of liquid, wavelength, frequency and
Ephoton=hv and λ=cv
Here, E represents the energy of the light, h represents the Plank’s constant, c is the speed of the light, →is the

Answer to Problem 119A
Energy for the first line is 3.38×10−19J and energy for the second line is 3.37×10−19J.
Explanation of Solution
Given Information:
The wavelength for the first line is 5.89×10−7m and the wavelength for the second line is 5.90×10−7m.
Calculation:
To determine the energies of the two lines, use the wavelength of the both lines. The wavelength for the first line is 5.89×10−7m and the wavelength for the second line is 5.90×10−7m. The value of h represents the Plank’s constant i.e. 6.626×10−34J.s and c represents the speed of the light is 3.00×108m/s.
E=hcλ
Calculation of energy for the first line as:
E=(6.626×10−34J.s)×(3.00×108m/s)(5.89×10−7m)=3.38×10−19J
Calculation of energy for the second line as:
E=(6.626×10−34J.s)×(3.00×108m/s)(5.90×10−7m)=3.37×10−19J
Hence, the energy for the first line is 3.38×10−19J and energy for the second line is 3.37×10−19J.
Energy for the first line is 3.38×10−19J and energy for the second line is 3.37×10−19J.
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