Chapter 5, Problem 7STP

Interpretation Introduction

Interpretation:

The element whose ground state electronic configuration is $\left[\text{Xe}\right]{\text{6s}}^{\text{2}}{\text{4f}}^{14}5{\text{d}}^6$ needs to be determined.

Concept introduction:

Electronic configurations of the elements are the distribution of electrons in the atomic orbitals. $2n^2$ formula is used for the determination of maximum number of electrons present in an orbit where $n$ is the number of orbit.

Answer to Problem 7STP

The correct option is D.

Explanation of Solution

The given electronic configuration of the unknown element is $\left[\text{Xe}\right]{\text{6s}}^{\text{2}}{\text{4f}}^{14}5{\text{d}}^6$. The atomic number of Xenon (Xe) is $54$. Therefore, the total number of electrons of the unknown element will be $54+2+14+6=76$. The atomic number of the given unknown element is $76$. The element with atomic number $76$ is Osmium in the periodic table. Hence, the correct option is D.

Conclusion

From the periodic table, element with atomic number $76$ is Osmium. Hence, the correct option is D.