The partial pressures of methane and ethane in the natural gas sample have to be calculated. The total mass of Water produced by the complete combustion of methane and ethane in the natural gas sample has to be determined. Concept Introduction: In a mixture of gaseous substances, the total pressure of the system is equal to the sum of the partial pressure of the each gaseous substance. Thus, the pressure contributed by the individual gaseous substance to the total pressure is known as the partial pressure of that gaseous substance. The partial pressure of a gas depends upon its mole fraction. Mole fraction of a gaseous component is nothing but the number of moles of that particular gaseous substance present in a system containing mixture of gaseous substances. Let us assume a system contains a mixture of two different gases A and B. Let ‘N’ be the total number of moles of gases present in the mixture. Then, Mole fraction of gas A is, X A = number of moles of A Total number of moles Mole fraction of gas B is, X B = number of moles of B Total number of moles Using the number of moles and mole fraction of the reactants and products, the amount of product obtained can be determined.

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Bookmarks Profiles Tab Window Help Chemical Formula - Aktiv Che X + → C 11 a app.aktiv.com Google Chrome isn't your default browser Set as default Question 12 of 16 Q Fri Feb 2 Verify it's you New Chrome availabl- Write the balanced molecular chemical equation for the reaction in aqueous solution for mercury(I) nitrate and chromium(VI) sulfate. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction. 3 Hg(NO3)2(aq) + Cг2(SO4)3(aq) → 3 Hg₂SO (s) + 2 Cr(NO3), (aq) ean Ui mate co ence an climate bility inc ulnerabili women, main critic CLIMATE-INI ernational + 10 O 2 W FEB 1 + 4- 3- 2- 2 2 ( 3 4 NS 28 2 ty 56 + 2+ 3+ 4+ 7 8 9 0 5 (s) (1) Ch O 8 9 (g) (aq) Hg NR CI Cr x H₂O A 80 Q A DII A F2 F3 FA F5 F6 F7 F8 F9 #3 EA $ do 50 % 6 CO & 7 E R T Y U 8 ( 9 0 F10 34 F11 川 F12 Subr + delete 0 { P }

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Chapter 5, Problem 164IP

Interpretation Introduction

Interpretation:

The partial pressures of methane and ethane in the natural gas sample have to be calculated.

The total mass of Water produced by the complete combustion of methane and ethane in the natural gas sample has to be determined.

Concept Introduction:

In a mixture of gaseous substances, the total pressure of the system is equal to the sum of the partial pressure of the each gaseous substance.

Thus, the pressure contributed by the individual gaseous substance to the total pressure is known as the partial pressure of that gaseous substance.

The partial pressure of a gas depends upon its mole fraction. Mole fraction of a gaseous component is nothing but the number of moles of that particular gaseous substance present in a system containing mixture of gaseous substances.

Let us assume a system contains a mixture of two different gases A and B. Let ‘N’ be the total number of moles of gases present in the mixture. Then,

Mole fraction of gas A is, XA= number of moles of ATotal number of moles

Mole fraction of gas B is, XB= number of moles of BTotal number of moles

Using the number of moles and mole fraction of the reactants and products, the amount of product obtained can be determined.

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Bookmarks Profiles Tab Window Help Chemical Formula - Aktiv Che X + → C 11 a app.aktiv.com Google Chrome isn't your default browser Set as default Question 12 of 16 Q Fri Feb 2 Verify it's you New Chrome availabl- Write the balanced molecular chemical equation for the reaction in aqueous solution for mercury(I) nitrate and chromium(VI) sulfate. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction. 3 Hg(NO3)2(aq) + Cг2(SO4)3(aq) → 3 Hg₂SO (s) + 2 Cr(NO3), (aq) ean Ui mate co ence an climate bility inc ulnerabili women, main critic CLIMATE-INI ernational + 10 O 2 W FEB 1 + 4- 3- 2- 2 2 ( 3 4 NS 28 2 ty 56 + 2+ 3+ 4+ 7 8 9 0 5 (s) (1) Ch O 8 9 (g) (aq) Hg NR CI Cr x H₂O A 80 Q A DII A F2 F3 FA F5 F6 F7 F8 F9 #3 EA $ do 50 % 6 CO & 7 E R T Y U 8 ( 9 0 F10 34 F11 川 F12 Subr + delete 0 { P }

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