In the “Méthode Champenoise,” grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is C 6 H 12 O 6 ( a q ) → 2C 2 H 5 OH ( a q ) + 2CO 2 ( g ) Fermentation of 750. mL grape juice (density = 1.0 g/cm 3 ) is allowed to take place in a bottle with a total volume of 825 mL until 12% by volume is ethanol (C 2 H 5 OH). Assuming that the CO 2 is insoluble in H 2 O (actually, a wrong assumption), what would be the pressure of CO 2 inside the wine bottle at 25°C? (The density of ethanol is 0.79 g/cm 3 .)
In the “Méthode Champenoise,” grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is C 6 H 12 O 6 ( a q ) → 2C 2 H 5 OH ( a q ) + 2CO 2 ( g ) Fermentation of 750. mL grape juice (density = 1.0 g/cm 3 ) is allowed to take place in a bottle with a total volume of 825 mL until 12% by volume is ethanol (C 2 H 5 OH). Assuming that the CO 2 is insoluble in H 2 O (actually, a wrong assumption), what would be the pressure of CO 2 inside the wine bottle at 25°C? (The density of ethanol is 0.79 g/cm 3 .)
Solution Summary: The author calculates the pressure of CO_ 2 gas produced in the given fermentation reaction of grape juice.
In the “Méthode Champenoise,” grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is
C
6
H
12
O
6
(
a
q
)
→
2C
2
H
5
OH
(
a
q
)
+
2CO
2
(
g
)
Fermentation of 750. mL grape juice (density = 1.0 g/cm3) is allowed to take place in a bottle with a total volume of 825 mL until 12% by volume is ethanol (C2H5OH). Assuming that the CO2 is insoluble in H2O (actually, a wrong assumption), what would be the pressure of CO2 inside the wine bottle at 25°C? (The density of ethanol is 0.79 g/cm3.)
Which of the following species is a valid resonance structure of A? Use curved arrows to show how A is converted to any valid resonance structure. When a compound is not a valid resonance structurc of A, explain why not.
Provide steps and tips on what to look for to understand how to solve and apply to other problems.
N
IZ
Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under
the table.
Molecule 1
Molecule 2
HN
Molecule 3
Х
HN
www.
Molecule 4
Molecule 5
Molecule 6
none of the above
NH
NH
G
Show work with explanation. don't give Ai generated solution
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