Chapter 5, Problem 151CP

Interpretation Introduction

Interpretation: The formula of hydrocarbon in the given reaction of combustion of this hydrocarbon with ${\text{O}}_2$ at $\text{0}\text{.959}\text{atm}$ and $\text{298}\text{K}$ is needed to be identified, if the combustion producing a mixture of ${\text{CO}}_{\text{2}}$ and ${\text{H}}_{\text{2}}\text{O}$ having a density of $\text{1}\text{.391}\text{g/L}$ and occupies a volume of 4 times larger than hydrocarbon.

Concept introduction:

• Number of moles of a substance,

• According to ideal gas equation,

$\text{Number}\text{of}\text{moles}\text{=}\frac{\text{Pressure}\times \text{Volume}}{\text{R}\text{×}\text{Temperature}}$

• Mass of a substance from its density and volume is,

$\text{Mass}\text{=}\text{Density}\times \text{Volume}$

Mass of a substance from its number of moles is,

$\text{Number of moles}\text{×}\text{Molecular}\text{mass in grams}\text{=}\text{taken}\text{Mass}$

• Balance equation of a reaction is written according to law of conservation of mass.
• Mole ratio between the reactants of a reaction is depends upon the coefficients of reactants in a balanced chemical equation.