Chapter 5, Problem 49E

Interpretation Introduction

Interpretation: For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at $\text{24°C}$.

Concept introduction:

By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law.

According to ideal gas law,

                                            $\text{PV=nRT}$

Where,

          P = pressure in atmospheres

          V= volumes in liters

          n = number of moles

          R =universal gas constant ( $0.08206L\cdot atm/K\cdot mol$)

          T = temperature in kelvins

By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation.

The mass of a given substance can be calculated by,

               $Massingram=numberofmoles\times grammolecularmass$