Chapter 5, Problem 12RP

To determine

To Calculate: The area of the paper used to construct the kite.

Answer to Problem 12RP

  $\text{Area of kite }=1176\text{sq}\text{. inches}$

Explanation of Solution

Given:

  

A kite.

Concept Used:

In kite adjacent sides are equal and longest diagonal is the perpendicular bisector of the shortest diagonal.

Calculation:

Here, we have

  

  $\begin{array}{l}\text{Area of kite }=\text{ Sum of area of triangles}\\ \Rightarrow \text{Area of kite }=ar\left(\Delta ABD\right)\text{ +}ar\left(\Delta BCD\right)\\ \Rightarrow \text{Area of kite }=\frac{1}{2}\times 36\times 42\text{+}\frac{1}{2}\times 42\times 20\\ \Rightarrow \text{Area of kite }=\frac{1}{2}\times 42\times \left(36+20\right)\\ \Rightarrow \text{Area of kite }=21\times 56\\ \Rightarrow \text{Area of kite }=1176\text{sq}\text{. inches}\end{array}$