Chapter 5, Problem 17RP

To determine

To Calculate: The area of the circle.

Answer to Problem 17RP

  $\text{Area of circle}=78.5\text{sq}\text{.units}$

Explanation of Solution

Given:

  

A circle with diametric end points

  $P\left(12,6\right)\text{ and T}\left(2,6\right)$

Concept Used:

Radius is the half part of the diameter.

Calculation:

Here, we have, a circle with diametric end points

  $P\left(12,6\right)\text{ and T}\left(2,6\right)$

  $\begin{array}{l}\text{Diameter of circle }=\sqrt{{\left(6-6\right)}^2+{\left(12-2\right)}^2}=\sqrt{{\left(10\right)}^2}=10units\\ \because \text{Radius of circle }=\frac{1}{2}\left(\text{Diameter of circle}\right)\\ \therefore \text{Radius of circle }=\frac{1}{2}\times 10units=5units\\ \therefore \text{Area of circle }=\pi r^2\\ \Rightarrow \text{Area of circle}=3.14\times 5^2\\ \Rightarrow \text{Area of circle}=3.14\times 25\\ \therefore \text{Area of circle}=78.5\text{sq}\text{.units}\end{array}$