Chapter 5.3, Problem 12PSA

To determine

To Find: The coordinate of midpoint of a side of a triangle of which x-coordinate is negative.

Answer to Problem 12PSA

  $\left(3,-3\right)$

Explanation of Solution

Given:

  

  $A=\left(-8,2\right),B=\left(14,-8\right)\text{and }C=\left(4,6\right)\text{vertices of triangle}\text{.}$

Concept Used:

  $\text{Coordinate of midpoint of line joining }\left(x_1,y_1\right)\text{and}\left(x_2,y_2\right)\text{is}=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$

Calculation:

Here, the side AB of which the coordinate of midpoint of a side of a triangle of which x-coordinate is negative.

  $\text{Coordinate of midpoint of line joining }A=\left(-8,2\right)\text{and }B=\left(14,-8\right)\text{is}=\left(\frac{-8+14}{2},\frac{2-8}{2}\right)=\left(3,-3\right)$