Chapter 5, Problem 3RP

To determine

Write an inequality stated the restriction on $x$ .

Answer to Problem 3RP

  $0<x<25$

Explanation of Solution

Given information:

  

Calculation:

Consider the given angles,

  $\left(x+50\right)°$ and $\left(3x°\right)$

As we know that $0<3x<x+50$

Subtract $x$ from both sides,

  $\begin{array}{l}0<3x-x<x-x+50\\ 0<2x<50\end{array}$

Now divide the whole inequality by $2$ to get $x$ in the middle for restriction value.

  $\begin{array}{l}\frac{0<2x<50}{2}\\ 0<x<25\end{array}$

Hence, the inequality is, $0<x<25$