Chapter 5.5, Problem 1PSA

To determine

To show: $\Delta ABC\cong \Delta CDA$ .

Explanation of Solution

Given information:

ABCD is a parallelogram.

  

Calculation:

ABCD is a parallelogram.

  

  $\begin{array}{l}\text{In above figure,}\\ \text{ABCD is a parallelogram}\text{. }\\ \angle ADC\cong \angle ABC\left\{\text{Opposite angles of a parallelogram}\right\}\\ \overline{AD}=\overline{BC}\left\{\text{Opposite sides of a parallelogram}\right\}\\ \overline{DC}=\overline{AB}\left\{\text{Opposite sides of a parallelogram}\right\}\\ \Delta ABC\cong \Delta CDA\left\{\text{Two triangles with two side and one angle equal}\right\}\end{array}$