Chemistry For Changing Times (14th Edition)
14th Edition
ISBN: 9780321972026
Author: John W. Hill, Terry W. McCreary
Publisher: PEARSON
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Question
Chapter 4, Problem 57P
(a)
Interpretation Introduction
Interpretation:
The shape of silane (SiH4) should be identified on the basis of VSEPR theory.
Concept introduction:
According to VSEPR theory, the shape of molecule depends upon the number of bonded pair of electron and lone pair of electron on central atom
- If there are two bonded groups the shape will be linear (AX)
- If there are three bonded groups the shape will be trigonal planar, with zero lone pair of electrons (AX2). If there is one lone pair of electrons the shape will be V (AXE).
- If there are four bonded groups the shape will be tetrahedral, with no lone pair of electrons (AX4). If there is one lone pair of electrons the shape will be trigonal pyramidal (AX3E). And if two lone pair of electrons the shape will be bent (AX2E2).
(b)
Interpretation Introduction
Interpretation:
The shape of hydrogen selenide (H2Se) should be identified on the basis of VSEPR theory.
Concept introduction:
According to VSEPR theory, the shape of molecule depends upon the number of bonded pair of electron and lone pair of electron on central atom
- If there are two bonded groups the shape will be linear (AX)
- If there are three bonded groups the shape will be trigonal planar, with zero lone pair of electrons (AX2). If there is one lone pair of electrons the shape will be V (AXE).
- If there are four bonded groups the shape will be tetrahedral, with no lone pair of electrons (AX4). If there is one lone pair of electrons the shape will be trigonal pyramidal (AX3E). And if two lone pair of electrons the shape will be bent (AX2E2).
(c)
Interpretation Introduction
Interpretation:
The shape of phosphine 
should be identified on the basis of VSEPR theory.
Concept introduction:
According to VSEPR theory, the shape of molecule depends upon the number of bonded pair of electron and lone pair of electron on central atom
- If there are two bonded groups the shape will be linear (AX)
- If there are three bonded groups the shape will be trigonal planar, with zero lone pair of electrons (AX2). If there is one lone pair of electrons the shape will be V (AXE).
- If there are four bonded groups the shape will be tetrahedral, with no lone pair of electrons (AX4). If there is one lone pair of electrons the shape will be trigonal pyramidal (AX3E). And if two lone pair of electrons the shape will be bent (AX2E2).
(d)
Interpretation Introduction
Interpretation:
The shape of silicon tetrafluoride (SiF4) should be identified on the basis of VSEPR theory.
Concept introduction:
According to VSEPR theory, the shape of molecule depends upon the number of bonded pair of electron and lone pair of electron on central atom
- If there are two bonded groups the shape will be linear (AX)
- If there are three bonded groups the shape will be trigonal planar, with zero lone pair of electrons (AX2). If there is one lone pair of electrons the shape will be V (AXE).
- If there are four bonded groups the shape will be tetrahedral, with no lone pair of electrons (AX4). If there is one lone pair of electrons the shape will be trigonal pyramidal (AX3E). And if two lone pair of electrons the shape will be bent (AX2E2).
(e)
Interpretation Introduction
Interpretation:
The shape of oxygen diflouride (OF2) should be identified on the basis of VSEPR theory.
Concept introduction:
According to VSEPR theory, the shape of molecule depends upon the number of bonded pair of electron and lone pair of electron on central atom
- If there are two bonded groups the shape will be linear (AX)
- If there are three bonded groups the shape will be trigonal planar, with zero lone pair of electrons (AX2). If there is one lone pair of electrons the shape will be V (AXE).
- If there are four bonded groups the shape will be tetrahedral, with no lone pair of electrons (AX4). If there is one lone pair of electrons the shape will be trigonal pyramidal (AX3E). And if two lone pair of electrons the shape will be bent (AX2E2).
(f)
Interpretation Introduction
Interpretation:
The shape of formaldehyde (H2CO) should be identified on the basis of VSEPR theory.
Concept introduction:
According to VSEPR theory, the shape of molecule depends upon the number of bonded pair of electron and lone pair of electron on central atom
- If there are two bonded groups the shape will be linear (AX)
- If there are three bonded groups the shape will be trigonal planar, with zero lone pair of electrons (AX2). If there is one lone pair of electrons the shape will be V (AXE).
- If there are four bonded groups the shape will be tetrahedral, with no lone pair of electrons (AX4). If there is one lone pair of electrons the shape will be trigonal pyramidal (AX3E). And if two lone pair of electrons the shape will be bent (AX2E2).
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Chapter 4 Solutions
Chemistry For Changing Times (14th Edition)
Ch. 4 - Prob. 1RQCh. 4 - Prob. 2RQCh. 4 - What are the structural differences among chlorine...Ch. 4 - Prob. 4RQCh. 4 - What are the charges on simple ions formed from...Ch. 4 - Prob. 6RQCh. 4 - In what group of the periodic table would elements...Ch. 4 - Prob. 8RQCh. 4 - Prob. 9RQCh. 4 - Prob. 10P
Ch. 4 - 11. Write Lewis symbols for each of the following...Ch. 4 - Write the Lewis symbol for each species in the...Ch. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - There are two common binary ionic compounds formed...Ch. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Use Lewis dot symbols to show the sharing of...Ch. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - 39. Supply a formula for the name or a name for...Ch. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Classify the bonds in the following as ionic or...Ch. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72APCh. 4 - Prob. 73APCh. 4 - Prob. 74APCh. 4 - Prob. 75APCh. 4 - Prob. 76APCh. 4 - Prob. 77APCh. 4 - Prob. 78APCh. 4 - Prob. 79APCh. 4 - Prob. 80APCh. 4 - Prob. 81APCh. 4 - Prob. 82APCh. 4 - Prob. 83APCh. 4 - Prob. 84APCh. 4 - Prob. 85APCh. 4 - Prob. 86APCh. 4 - Prob. 87APCh. 4 - Prob. 88APCh. 4 - Prob. 89APCh. 4 - Prob. 90APCh. 4 - Prob. 91APCh. 4 - Prob. 92APCh. 4 - Prob. 93APCh. 4 - Prob. 4.1CTECh. 4 - Prob. 4.2CTECh. 4 - 4.3 Sodium chloride (NaCI) is a metal-nonmetal...Ch. 4 - Prob. 4.4CTECh. 4 - Prob. 4.5CTECh. 4 - Prob. 4.6CTECh. 4 - Prob. 4.7CTECh. 4 - Prob. 4.8CTECh. 4 - Prob. 4.9CTECh. 4 - Prob. 4.10CTECh. 4 - Prob. 1CGPCh. 4 - Prob. 2CGPCh. 4 - Prepare a PowerPoint, poster, or other...Ch. 4 - Prob. 4CGPCh. 4 - Prob. 5CGPCh. 4 - Prob. 1CHQCh. 4 - Prob. 2CHQCh. 4 - Prob. 3CHQ
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