Chemistry For Changing Times (14th Edition)
Chemistry For Changing Times (14th Edition)
14th Edition
ISBN: 9780321972026
Author: John W. Hill, Terry W. McCreary
Publisher: PEARSON
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Chapter 4, Problem 58P

(a)

Interpretation Introduction

Interpretation:

Assign the correct shape / geometry to Chemistry For Changing Times (14th Edition), Chapter 4, Problem 58P , additional homework tip  1(chloroform), based on VSEPR theory.

Concept introduction:

According to VSEPR theory we can determine the shape of a molecule by following the given steps

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
  5. Bond pair-bond pair < lone pair −bond pair < lone pair-lone pair.

(b)

Interpretation Introduction

Interpretation:

Assign the correct shape / geometry to Chemistry For Changing Times (14th Edition), Chapter 4, Problem 58P , additional homework tip  2(boron trichloride), based on VSEPR theory.

Concept introduction:

According to VSEPR theory we can determine the shape of a molecule by following the given steps

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
  5. Bond pair -bond pair < lone pair −bond pair < lone pair-lone pair.

(c)

Interpretation Introduction

Interpretation:

Assign the correct shape / geometry to Chemistry For Changing Times (14th Edition), Chapter 4, Problem 58P , additional homework tip  3(carbon tetrafluoride), based on VSEPR theory.

Concept introduction:

According to VSEPR theory we can determine the shape of a molecule by following the given steps

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
  5. Bond pair--bond pair< lone pair −bond pair < lone pair-lone pair.

(d)

Interpretation Introduction

Interpretation:

Assign the correct shape / geometry to Chemistry For Changing Times (14th Edition), Chapter 4, Problem 58P , additional homework tip  4(sulfur difluoride), based on VSEPR theory.

Concept introduction:

According to VSEPR theory we can determine the shape of a molecule by following the given steps

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
  5. Bond pair-bond pair < lone pair −bond pair < lone pair-lone pair.

(e)

Interpretation Introduction

Interpretation:

Assign the correct shape / geometry to Chemistry For Changing Times (14th Edition), Chapter 4, Problem 58P , additional homework tip  5(Nitrogen triiodide), based on VSEPR theory.

Concept introduction:

According to VSEPR theory we can determine the shape of a molecule by following the given steps

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
  5. Bond pair-bond pair < lone pair −bond pair < lone pair-lone pair.

(f)

Interpretation Introduction

Interpretation:

Assign the correct shape / geometry toChemistry For Changing Times (14th Edition), Chapter 4, Problem 58P , additional homework tip  6(Dichlorodifluoromethane), based on VSEPR theory.

Concept introduction:

According to VSEPR theory we can determine the shape of a molecule by following the given steps

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
  5. Bond pair-bond pair < lone pair −bond pair < lone pair-lone pair.

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Chapter 4 Solutions

Chemistry For Changing Times (14th Edition)

Ch. 4 - 11. Write Lewis symbols for each of the following...Ch. 4 - Write the Lewis symbol for each species in the...Ch. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - There are two common binary ionic compounds formed...Ch. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Use Lewis dot symbols to show the sharing of...Ch. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - 39. Supply a formula for the name or a name for...Ch. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Classify the bonds in the following as ionic or...Ch. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72APCh. 4 - Prob. 73APCh. 4 - Prob. 74APCh. 4 - Prob. 75APCh. 4 - Prob. 76APCh. 4 - Prob. 77APCh. 4 - Prob. 78APCh. 4 - Prob. 79APCh. 4 - Prob. 80APCh. 4 - Prob. 81APCh. 4 - Prob. 82APCh. 4 - Prob. 83APCh. 4 - Prob. 84APCh. 4 - Prob. 85APCh. 4 - Prob. 86APCh. 4 - Prob. 87APCh. 4 - Prob. 88APCh. 4 - Prob. 89APCh. 4 - Prob. 90APCh. 4 - Prob. 91APCh. 4 - Prob. 92APCh. 4 - Prob. 93APCh. 4 - Prob. 4.1CTECh. 4 - Prob. 4.2CTECh. 4 - 4.3 Sodium chloride (NaCI) is a metal-nonmetal...Ch. 4 - Prob. 4.4CTECh. 4 - Prob. 4.5CTECh. 4 - Prob. 4.6CTECh. 4 - Prob. 4.7CTECh. 4 - Prob. 4.8CTECh. 4 - Prob. 4.9CTECh. 4 - Prob. 4.10CTECh. 4 - Prob. 1CGPCh. 4 - Prob. 2CGPCh. 4 - Prepare a PowerPoint, poster, or other...Ch. 4 - Prob. 4CGPCh. 4 - Prob. 5CGPCh. 4 - Prob. 1CHQCh. 4 - Prob. 2CHQCh. 4 - Prob. 3CHQ
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