The electronegativity difference between X and Y elements so the covalent bond will be non-polar should be determined. Concept Introduction: Valence electron: The electrons which are present in the outer most energy level are known as valence electron. This can be calculated by the group number of the element. Generally, the group number is same as the valence electrons of any elements. Octet rule: Generally, all atoms will lose, gain or share electrons to attain 8 valence electrons; the electron configuration of the nearest noble element. The covalent bond is a type of bond which formed by sharing of electrons between atoms. It forms between two non-metals.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4, Problem 46P

Interpretation Introduction

Interpretation:

The electronegativity difference between X and Y elements so the covalent bond will be non-polar should be determined.

Concept Introduction:

Valence electron: The electrons which are present in the outer most energy level are known as valence electron. This can be calculated by the group number of the element. Generally, the group number is same as the valence electrons of any elements.

Octet rule: Generally, all atoms will lose, gain or share electrons to attain 8 valence electrons; the electron configuration of the nearest noble element.

The covalent bond is a type of bond which formed by sharing of electrons between atoms. It forms between two non-metals.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below. Find the following: (a) The no. of protons corresponding to each signal in the spectra (6) Give the structure of the compound and assign the signals to each proton in the compound. a 70.2 Integration Values C5H10O2 b 47.7 C 46.5 d 69.5 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 Chemical Shift (ppm) 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8

Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below. Answer the following: (a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure of the molecule below. (b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible. complex splitting patterns assuming J values are not similar. там Br 22 2 3 6 4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0 Chemical Shift (ppm) ra. Br 2 3 6 6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 Chemical Shift (ppm) 2 2 Br 7.3 7.2 7.1 7.0 6.9 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0 Chemical Shift (ppm) 5.9 5.8 5.7 5.5 5.4 5.3 5.2 5.0 4.9

1600° 1538°C 1493°C In the diagram, the letter L indicates that it is a liquid. Indicate its components in the upper region where only L is indicated. The iron-iron carbide phase diagram. Temperature (°C) 1400 8 1394°C y+L 1200 2.14 y, Austenite 10000 912°C 800a 0.76 0.022 600 400 (Fe) a, Ferrite Composition (at% C) 15 1147°C a + Fe3C 2 3 Composition (wt% C) L 2500 4.30 2000 y + Fe3C 727°C 1500 Cementite (Fe3C) 1000 4 5 6 6.70 Temperature (°F)