(a)
Interpretation:
The number of elements that forms a negatively charged ions among the following highlighted elements in the below periodic table has to be identified.
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
(b)
Interpretation:
The elements that forms ions through gain of electrons among the following highlighted elements in the below periodic table has to be identified.
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
(c)
Interpretation:
The elements which forms ions that has a charge magnitude of
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
(d)
Interpretation:
The elements that forms an ion that involves loss of two or more electrons among the following highlighted elements in the below periodic table has to be identified.
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
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Chapter 4 Solutions
General, Organic, and Biological Chemistry
- Please correct answer and don't used hand raitingarrow_forward(a) The following synthesis of the molecule shown in the circle has a major problem. What is this problem? (2 pts) 1) HBr (no peroxides) 2) H- NaNH2 Br 3) NaNH, 4) CH3Br 5) H2, Pd (b) Starting with the molecule shown below and any other materials with two carbons or less, write out an alternate synthesis of the circled molecule. More than one step is needed. Indicate the reagent(s) and the major product in all the steps in your synthesis. (5 pts) 2024 Fall Term (1) Organic Chemistry 1 (Lec) CHEM 22204 02[6386] (Hunter College) (c) Using the same starting material as in part (b) and any other materials win two carpons or less, write out syntheses of the circled molecules shown below. More than one step is needed in each case. Indicate the reagent(s) and the major product in all the steps in your synthesis. You may use reactions and products from your synthesis in part (b). (5 pts)arrow_forwardalt ons for Free Response Questions FRQ 1: 0/5 To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and some inert materials, solutions with known [Co?) are prepared and absorbance of each of the solutions is measured at the wavelength of optimum absorbance. The data are used to create a calibration plot, shown below. 0.90- 0.80- 0.70 0.60 0.50 0.40- 0.30 0.20- 0.10- 0.00- 0.005 0.010 Concentration (M) 0.015 A 0.630 g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted with water to a final volume of 50.00 ml. Assume that all the cobalt in the ore sample is converted to Co2+(aq). a. What is the [Co2] in the solution if the absorbance of a sample of the solution is 0.74? 13 ✗ b. Calculate the number of moles of Co2+(aq) in the 50.00 mL solution. 0.008 mols Coarrow_forward
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