Materials for Civil and Construction Engineers (4th Edition)
4th Edition
ISBN: 9780134320533
Author: Michael S. Mamlouk, John P. Zaniewski
Publisher: PEARSON
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Chapter 4, Problem 4.2QP
To determine
Complete the table for a member where deflection controls, which material require a larger cross section, and for a member where tension controls.
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Complete Table P4.2. For a member where a deflection criterion controls,which material would require a larger cross section? What about for a member where tension controls?
6. Give the properties table below.
A992 Steel
7178 T76 Aluminum
Yield Strength
50 ksi
73 ksi
Ultimate strength
75 ksi
85 ksi
Modulus of Elasticity
29,000 ksi
10,500 ksi
Assume you are designing a rectangular member with a specific allowed height.
For a design where deflection criterion controls which material would require a larger cross
section?
For a design where tension stress controls, which material requires the larger cross section?
} 8) A tensile load of 3000 N is applied to a steel bar of cross-sectional area 500 mm?. If
a tensile load was applied to an aluminum bar to achieve the same lateral (transvers) strain
with the former (steel bar), what would be the load?
Note: Original dimensions of the two bars are the same
(Est = 2.1 x 105 MPa, Eat = 0.703 × 105 MPa, vg = 0.3, vat = 0.33) E = º , v = - Saterat
Eaxial
Fatuminum™
3000 N
A-500 mm²
A=500 mm²
Fatuminum=?
3000 N
Steel
Aluminum
Chapter 4 Solutions
Materials for Civil and Construction Engineers (4th Edition)
Ch. 4 - Name the two primary factors that make aluminum an...Ch. 4 - Prob. 4.2QPCh. 4 - An aluminum alloy specimen with a radius of 0.28...Ch. 4 - An aluminum alloy bar with a radius of 7 mm was...Ch. 4 - Decode the characteristics of a 6063 T831...Ch. 4 - A round aluminum alloy bar with a 0.6 in. diameter...Ch. 4 - An aluminum alloy bar with a rectangular cross...Ch. 4 - A round aluminum alloy bar with a 0.25-in....Ch. 4 - An aluminum alloy rod has a circular cross section...Ch. 4 - An aluminum alloy cylinder with a diameter of 3...
Ch. 4 - A 3003-H14 aluminum alloy rod with 0.5 in....Ch. 4 - The stressstrain relation of an aluminum alloy bar...Ch. 4 - An aluminum specimen originally 300 mm long is...Ch. 4 - A tension stress of 40 ksi was applied on a 12-in....Ch. 4 - A tension test was performed on an aluminum alloy...Ch. 4 - In Problem 4.15, plot the stressstrain...Ch. 4 - Referring to Figure 4.5, determine approximate...Ch. 4 - Prob. 4.18QPCh. 4 - A tensile stress is applied along the long axis of...Ch. 4 - A cylindrical aluminum alloy rod with a 0.5 in....Ch. 4 - Prob. 4.21QPCh. 4 - Discuss galvanic corrosion of aluminum. How can...
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- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.arrow_forwardvalue for modulus of elasticty for steel is 29000 ksi and for aluminum it is 10000ksi. yield strength for steel is 36 ksi and yield strength for aluminum is 37 ksiarrow_forwardQ5 A specimen of magnesium having a rectangular cross section of dimensions (3.2 mm X 19.1 mm) and gage length 63.5 mm is deformed in tension. Using the load-elongation data tabulated as follows load (N) and Extension (mm), Find the standard mechanical properties. load 1380 2780 5630 7430 8140 9870 12850 | 14100 14340 13830 12500 Ext. 0.03 0.06 0.12 0.2 0.25 0.64 1.91 3.18 4.45 5.72 6.99 a) Draw the stress strain curve. b) Find the young modulus. c) Find the proof stress d) Find the ultimate tensile strength. e) Find the fracture stress f) Find the maximum strain.arrow_forward
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