Materials for Civil and Construction Engineers (4th Edition)
Materials for Civil and Construction Engineers (4th Edition)
4th Edition
ISBN: 9780134320533
Author: Michael S. Mamlouk, John P. Zaniewski
Publisher: PEARSON
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Chapter 4, Problem 4.15QP

A tension test was performed on an aluminum alloy specimen to fracture. The original diameter of the specimen is 0.5 in. and the gauge length is 2.0 in. The information obtained from this experiment consists of applied tensile load (P) and increase in length (ΔL). The results are tabulated in Table P4.15. Using a spreadsheet program, complete the table by calculating engineering stress (σ) and engineering strain (ε). Determine the toughness of the material (ut) by calculating the area under the stress–strain curve, namely,

u t = 0 ε f σdε

where εf is the strain at fracture. The preceding integral can be approximated numerically using a trapezoidal integration technique:

u t = i = 1 n u i = i = 1 n 1 2 ( σ i + σ i 1 ) ( ε i ε i 1 )

Chapter 4, Problem 4.15QP, A tension test was performed on an aluminum alloy specimen to fracture. The original diameter of the

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A tensile test specimen of aluminum alloy having a diameter of 0.5 in. and a gage length of 2 in. was tested to fracture. The complete stress-strain diagram for this specimen is shown below to the left. The small strain portion of this diagram has been enlarged (to the right) to show in more detail the linear portion of the stress-strain diagram. Determine (a) Young's modulus or modulus of elasticity (i.e., the slope of linear portion), (b) yield stress (using the so-called 0.2% offset method from the lecture notes), (c) yield strain (i.e., the strain corresponding to yield stress, not the 0.2%!), (d) ultimate strength (i.e., the peak in stress-strain diagram), (e) rupture stress (i.e., stress at breaking/failure), (f) rupture strain (i.e., the strain corresponding to rupture stress). 80 70 70 60 60 50 50 40 30 30 20 20 10 10 0.005 0.01 0.015 0.02 Strain (in/in) Strain (in/in) Stress (ksi) 0.015 - 0.03 - 0.12 - 0.135 - 0.15 Stress (ksi)
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Please answer d,e,f
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