Materials for Civil and Construction Engineers (4th Edition)
4th Edition
ISBN: 9780134320533
Author: Michael S. Mamlouk, John P. Zaniewski
Publisher: PEARSON
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Chapter 4, Problem 4.21QP
To determine
The difference in depth required for an aluminum beam compared to a steel beam in order to obtain the equal deflection.
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12. Assume a uniformly load simply support beam with a rectangular cross section. The width of
the beam is fixed by other design considerations. Determine the ratio between the difference in
depth required for an aluminum beam compared to a steel beam in order to obtain the same
maximum deflection.
MOE aluminum can be taken as 10,000 ksi, for steel as 30,000 ksi.
The maximum deflection for the beam is 5wl*/384EI
Factoring the deflection equations we can conclude that for equal deflection Eala = Esls where
subscripts a and s represent values for aluminum and steel.
The depth of
must be
times the depth of the
Assume a uniformly loaded simply supported beam with a rectangular cross
section. The width of the beam is fixed by other design considerations. Deter-mine the difference in depth required for an aluminum beam compared to a
steel beam in order to obtain the same maximum deflection.
What is the maximum concentrated load that can be applied at the end of an embedded hollow pipe, made of AISI 1020 steel? Take 10.16 cm for the outside diameter, and 6.35 cm for the inside diameter. The length of the pipe is 183 cm. Its maximum deflection must not exceed 5.08 cm. Neglect the weight of the pipe.
Answer 22816 N
Chapter 4 Solutions
Materials for Civil and Construction Engineers (4th Edition)
Ch. 4 - Name the two primary factors that make aluminum an...Ch. 4 - Prob. 4.2QPCh. 4 - An aluminum alloy specimen with a radius of 0.28...Ch. 4 - An aluminum alloy bar with a radius of 7 mm was...Ch. 4 - Decode the characteristics of a 6063 T831...Ch. 4 - A round aluminum alloy bar with a 0.6 in. diameter...Ch. 4 - An aluminum alloy bar with a rectangular cross...Ch. 4 - A round aluminum alloy bar with a 0.25-in....Ch. 4 - An aluminum alloy rod has a circular cross section...Ch. 4 - An aluminum alloy cylinder with a diameter of 3...
Ch. 4 - A 3003-H14 aluminum alloy rod with 0.5 in....Ch. 4 - The stressstrain relation of an aluminum alloy bar...Ch. 4 - An aluminum specimen originally 300 mm long is...Ch. 4 - A tension stress of 40 ksi was applied on a 12-in....Ch. 4 - A tension test was performed on an aluminum alloy...Ch. 4 - In Problem 4.15, plot the stressstrain...Ch. 4 - Referring to Figure 4.5, determine approximate...Ch. 4 - Prob. 4.18QPCh. 4 - A tensile stress is applied along the long axis of...Ch. 4 - A cylindrical aluminum alloy rod with a 0.5 in....Ch. 4 - Prob. 4.21QPCh. 4 - Discuss galvanic corrosion of aluminum. How can...
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- Give me right solution A steel bar that is 28 feet long is subjected to a 251 kip load. Maximum allowable deflection must not exceed 0.28 inches. What is the required area based on maximum allowable deformation? (in2)arrow_forwardvalue for modulus of elasticty for steel is 29000 ksi and for aluminum it is 10000ksi. yield strength for steel is 36 ksi and yield strength for aluminum is 37 ksiarrow_forwardPlease show intermediate steps including free body diagrams, equations used, and problem setup so that your approach can be followed.arrow_forward
- The assembly shown is composed of a steel shell and an aluminum core that has been welded to a rigid plate. The gap between the plate and the steel shell is 1- mm. If the assembly's temperature is reduced by 180°C, determine (a) the final axial stresses in each material and (b) the deflection of the rigid bar. To support your response, draw a deformation diagram with appropriate labels. Use the following properties: Aluminum core Steel shell Diameters (mm) d = 15 mm do = 30 mm d₁ = 20 mm E (GPa) 70 200 2 m a (/°C) 22 x 10-6 12 x 10-6arrow_forwardA round steel bar carries a evenly distributed load of 2KN per meter and it is 5 meter long , The bar is a cantilever bar fixed at both ends. It also carries a a load of 30KN in the middle of the bar. The diameter of the bar is 50mm and modulus is 207 GPa.If the total deflection that will be produced in the bar must be limited to 0.005 mm , what should be the yield stength of the material ?arrow_forwardThe rubber band given below is subjected to the following tensile loading. Calculate the minimum thickness of the rubber (tr) and the minimum steel pin diameter (Dpin) so that the structure does not fail. Consider: Allowable tensile strength of the rubber= 20MPa Allowable shear strength of the steel = 200MPa Reflection: 1) How would you solve this problem if a Factor of Safety was given? 2) Are there any other dimensions worth calculating for the rubber belt?arrow_forward
- Find the lightest S-shape for the beam shown if the working stress in bending is 175 MPa. What is the maximum bending stress in the beam selected? 50 kN/m 4 m -2.4 m· -x X- TABLE B-3 Properties of I-Beam Sections (S-Shapes): SI Units Flange Axis Y-Y Web X-X spxy Mass Area Width ıdə (wu) Thickness thickness Pl1 = S (10³ mm³) yli^ = 4 (10° mm*) (u) 27.7 27.7 22.1 Designation (10° mm*) (ww) 20.3 (ww) 38.9 („ww) (ww) (ww) 081 158 006 77 622 622 204 1 320 1 220 081 x 019S 4 230 240 34.5 338 × 158 x 149 x 134 007 184 15.7 3930 3 260 247 O'ZE 19.7 320 001 07 6'6E 32.3 006 81 00 I 15 200 149 6'81 15.9 166 937 677 234 019 215 134 181 22.1 090 € 2870 019 18.6 205 33.0 611 22.1 12.7 874 241 17.5 197 61I x 34.0 019 S510 × 143 143 18 200 16300 14 200 12 500 91S 91S 183 23.4 23.4 20.2 20.3 16.8 S69 653 2 700 20.8 228 x 128 x 112 × 98.2 128 112 33.8 34.5 29.5 179 961 2 540 007 194 19.4 80s 508 216 152 162 16.1 533 001 7 1950 12.3 98.2 20.2 12.8 495 6SI 11.4 144 30.2 661 S460 × 104 104 13 200 457 6SI…arrow_forwardComplete Table P4.2. For a member where a deflection criterion controls, which material would require a larger cross section? What about for a member where tension controls? TABLE P4.2 Mild Steel 7178 T76 Aluminum Yield Strength Ultimate Strength Modulus of Elasticityarrow_forwardStress in segment bronze and steelarrow_forward
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