The potential difference by which a proton must be accelerated to have wavelength of λ = 6.0 × 10 − 12 m .

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Answer 1

Question

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

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Students have asked these similar questions

Calculate the momentum of an X-ray photon with a wavelength of 0.17nm. H80 this value compare with the momentum of a free electron that has been accelerated through a potential difference of 5000 volts? (Hint: electron mass, m, = 9.10938 x 10" kg; electron charge e = 1.602 x 10"C; speed of light e = 3.0 x 10' m.s'; 1.00 J=1.00 VC; h = 6.626 x 10"J.s. The various energy units are: 1 J= 1 kg.m's³, 1.00 eV -1VC, leV = 1.602 x 10 "J, 1J - 6.242 x 10" eV, etc.).

An electron and a photon each have a wavelength of 0.20 nm.What is the momentum (in kg m/s) of the (a) electron and (b) photon? What is the energy (in eV) of the (c) electron and (d) photon?

During a certain experiment, the de Broglie wavelength of an electron is 400 nm = 4.0 ✕ 10−7 m, which is the same as the wavelength of violet light. How fast (in m/s) is the electron moving?

Answer 2

Question

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

Expert Solution & Answer

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Answer 3

Question

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

Expert Solution & Answer

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Answer 4

Question

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 5

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

Answer 6

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

Answer 7

Chapter 37, Problem 80GP

(a)

To determine

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

Answer 8

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

Answer 9

(b)

To determine

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. 37.2 - Prob. 1AE Ch. 37.2 - Prob. 1BE Ch. 37.4 - Prob. 1CE Ch. 37.7 - Prob. 1DE Ch. 37.7 - Prob. 1EE Ch. 37.11 - Prob. 1FE Ch. 37 - Prob. 1Q Ch. 37 - Prob. 2Q Ch. 37 - Prob. 3Q Ch. 37 - Prob. 4Q

The potential difference by which a proton must be accelerated to have wavelength of λ = 6.0 × 10 − 12 m .

Solution Summary: The author explains the potential difference by which a proton must be accelerated to have wavelength of lambda =6.0. Write the expression to calculate the momentum from de Broglie's relation.

Concept explainers

The potential difference by which a proton must be accelerated to have wavelength of λ=6.0×10−12 m.

The potential difference by which an electron must be accelerated to have wavelength λ=6.0×10−12 m.

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Chapter 37 Solutions