Chapter 37, Problem 44A

How does the current in the secondary of a transformer compare with the current in the primary when the secondary voltage is twice the primary voltage?

To determine

To calculate: the current in the secondary coil of transformer when the secondary voltage is twice the primary voltage.

Answer to Problem 44A

The current would be $2$ times less in the secondary coil.

Explanation of Solution

Introduction:

The power input should be equal to the power output.

The power of the transformer is given as :

$\begin{array}{l}{P}_{in}=V_P{I}_P\\ P_{out}=V_S{I}_S\end{array}$

Here,

${\mathrm{V}}_P\&V_S$ = primary and secondary voltage

${\mathrm{I}}_P\&I_S$ = primary and secondary current.

As the power of the transformer will be same so as the voltage become twice the primary voltage, the current would be 2 times less in the secondary coil.

Conclusion:

As the voltage increases in the secondary coil, the current will be reduced to equalize the power.