Chapter 37, Problem 14A

If the number of secondary turns is 10 times the number of primary turns, and the input voltage to the primary is 6 volts, how many volts will be induced in the secondary coil?

To determine

To find: induced voltage in secondary coil if number of secondary turns is 10 times the number of primary turns and input voltage to primary coil is 6 volts.

Answer to Problem 14A

Induced voltage in secondary coil is 60 volts.

Explanation of Solution

Given info:

Input voltage to primary, $V_P=6V$

Number of secondary turns = 10 $\times$ Number of primary turns, $N_S=10N_P$

Formula used:

  $\frac{V_S}{V_P}=\frac{N_S}{N_P}$

Calculation:

Substitute values in formula,

  $\begin{array}{l}\frac{V_S}{6}=\frac{10N_P}{N_P}\\ \frac{V_S}{6}=10\\ V_S=10\times 6=60V\end{array}$

Conclusion:

Induced voltage in secondary coil is 60 volts.