Explanation 1) Concept: By using Bragg’s diffraction condition, we can find the inter-planar spacing between the two planes and also the wavelength of the first order reflection. 2) Formula: 2 d sin ⁡ θ = m λ 3) Given: i) θ 1 = 23 ° ii) θ 2 = 60 ° iii) λ 1 = A iv) λ 2 = 97 p m v) m 1 = 1 vi) m 2 = 3 4) Calculations: a) First, we can calculate the inter-planar spacing by using Bragg’s condition. For the second beam undergoing the third-order reflection, 2 d sin ⁡ θ 2 = m 2 λ 2 d = m 2 λ B 2 sin ⁡ θ 2 d = 3 × 97 × 10 - 12 </

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Question

Chapter 36, Problem 65P

To determine

To find:

a) The inter-planar spacing

b) The wavelength A

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Chapter 36, Problem 64P

Chapter 36, Problem 66P

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An x-ray beam of wavelength A undergoes first-order reflection (Bragg law diffraction) from a crystal when its angle of incidence to a crystal face is 23°, and an x-ray beam of wavelength 97 pm undergoes third-order reflection when its angle of incidence to that face is 60°. Assuming that the two beams reflect from the same family of reflecting planes, find (a) the interplanar spacing and (b) the wavelength A.

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Chapter 36 Solutions

Fundamentals of Physics Extended

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a) The inter-planar spacing b) The wavelength A

Solution Summary: The author explains how Bragg's diftion condition calculates the inter-planar spacing between the two planes and the wavelength of the first-order reflection.

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To find: a) The inter-planar spacing b) The wavelength A

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Chapter 36 Solutions

To find:

a) The inter-planar spacing

b) The wavelength A