GO Floaters . The floaters you see when viewing a bright, featureless background are diffraction patterns of defects in the vitreous humor that fills most of your eye. Sighting through a pinhole sharpens the diffraction pattern. If you also view a small circular dot, you can approximate the defect’s size. Assume that the defect diffracts light as a circular aperture does. Adjust the dot’s distance L from your eye (or eye lens) until the dot and the circle of the first minimum in the diffraction pattern appear to have the same size in your view. That is, until they have the same diameter D ʹ on the retina at distance L ʹ = 2.0 cm from the front of the eye, as suggested in Fig. 36-42 a , where the angles on the two sides of the eye lens are equal. Assume that the wavelength of visible light is λ = 550 nm. If the dot has diameter D = 2.0 mm and is distance L = 45.0 cm from the eye and the defect is x = 6.0 mm in front of the retina (Fig. 36-42 b ), what is the diameter of the defect? Figure 36-42 Problem 30.
GO Floaters . The floaters you see when viewing a bright, featureless background are diffraction patterns of defects in the vitreous humor that fills most of your eye. Sighting through a pinhole sharpens the diffraction pattern. If you also view a small circular dot, you can approximate the defect’s size. Assume that the defect diffracts light as a circular aperture does. Adjust the dot’s distance L from your eye (or eye lens) until the dot and the circle of the first minimum in the diffraction pattern appear to have the same size in your view. That is, until they have the same diameter D ʹ on the retina at distance L ʹ = 2.0 cm from the front of the eye, as suggested in Fig. 36-42 a , where the angles on the two sides of the eye lens are equal. Assume that the wavelength of visible light is λ = 550 nm. If the dot has diameter D = 2.0 mm and is distance L = 45.0 cm from the eye and the defect is x = 6.0 mm in front of the retina (Fig. 36-42 b ), what is the diameter of the defect? Figure 36-42 Problem 30.
GOFloaters. The floaters you see when viewing a bright, featureless background are diffraction patterns of defects in the vitreous humor that fills most of your eye. Sighting through a pinhole sharpens the diffraction pattern. If you also view a small circular dot, you can approximate the defect’s size. Assume that the defect diffracts light as a circular aperture does. Adjust the dot’s distance L from your eye (or eye lens) until the dot and the circle of the first minimum in the diffraction pattern appear to have the same size in your view. That is, until they have the same diameter Dʹ on the retina at distance Lʹ = 2.0 cm from the front of the eye, as suggested in Fig. 36-42a, where the angles on the two sides of the eye lens are equal. Assume that the wavelength of visible light is λ = 550 nm. If the dot has diameter D = 2.0 mm and is distance L = 45.0 cm from the eye and the defect is x = 6.0 mm in front of the retina (Fig. 36-42b), what is the diameter of the defect?
3.63 • Leaping the River II. A physics professor did daredevil
stunts in his spare time. His last stunt was an attempt to jump across
a river on a motorcycle (Fig. P3.63). The takeoff ramp was inclined at
53.0°, the river was 40.0 m wide, and the far bank was 15.0 m lower
than the top of the ramp. The river itself was 100 m below the ramp.
Ignore air resistance. (a) What should his speed have been at the top of
the ramp to have just made it to the edge of the far bank? (b) If his speed
was only half the value found in part (a), where did he land?
Figure P3.63
53.0°
100 m
40.0 m→
15.0 m
Please solve and answer the question correctly please. Thank you!!
You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 5.00 s after it was thrown. What is the speed of the rock just before it reaches the water 25.0 m below the point where the rock left your hand? Ignore air resistance.
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