Explanation 1) Concept: When light waves encounter an edge or an obstacle of size comparable to the wavelength of the waves, those waves spread out and undergo interference and give diffraction pattern. And by using diffraction condition, one can find out wavelengths that pass through the slit. 2) Formula: i) Condition for diffraction maxima d s i n θ = m λ 3) Given: i) A grating has 1 d = 350 r u l i n g s / m m ii) This grating is illuminated at normal incidence by white light. iii) A spectrum is formed on a screen D = 30 cm from the grating. iv) Side length of square hole, 10.0 m m is cut on the screen. v) Inner edge of square hole from the central maximum is, 50.0 m m , and is parallel to it. 4) Calculations: a) d for given grating d = 1 350 m m = 0.00285 m m = 0.00285 × 10 6 n m By using diffraction condition, we get m = d s i n θ λ = 0.00285 × 10 6 n m × s i n θ λ We have t a n θ = 5.0 c m 30 c m = 0.1666 tan - 1 ⁡ 0

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Question

Chapter 36, Problem 53P

To determine

To find

a) the shortest wavelength of the light that passes through the hole.

b) the longest wavelength of the light that passes through the hole.

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Chapter 36, Problem 52P

Chapter 36, Problem 54P

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Chapter 36 Solutions

Fundamentals of Physics Extended

Ch. 36 - You are conducting a single-slit diffraction...Ch. 36 - In a single-slit diffraction experiment, the top...Ch. 36 - For three experiments, Fig. 36-30 gives the...Ch. 36 - For three experiments, Fig. 36-31 gives versus...Ch. 36 - Figure 36-32 shows four choices for the...Ch. 36 - Prob. 6Q Ch. 36 - At night many people see rings called entoptic...Ch. 36 - a For a given diffraction grating, does the...Ch. 36 - Figure 36-33 shows a red line and a green line of...Ch. 36 - For the situation of Question 9 and Fig. 36-33, if...

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To find a) the shortest wavelength of the light that passes through the hole. b) the longest wavelength of the light that passes through the hole.

Solution Summary: The author explains that light waves encounter an edge or an obstacle of size comparable to the wavelength of the waves and undergo interference and give diftion pattern.

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To find a) the shortest wavelength of the light that passes through the hole. b) the longest wavelength of the light that passes through the hole.

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Chapter 36 Solutions

To find

a) the shortest wavelength of the light that passes through the hole.

b) the longest wavelength of the light that passes through the hole.